Answer:
Explanation:
The code does not fail on the first step since 1900 divided by 4 is actually 475 and has no remainder, meaning that it should return True. The code won't work because the if statements need to be nested in a different format. The correct algorithm would be the following, which can also be seen in the picture attached below that if we input 1900 it would output is not a leap year as it fails on the division by 400 which gives a remainder of 0.75
input_year = int(input())
if input_year % 4 == 0:
if input_year % 100 == 0:
if input_year % 400 == 0:
print(input_year, "is a leap year")
else:
print(input_year, "- not a leap year")
else:
print(input_year, "is a leap year")
else:
print(input_year, "- not a leap year")
I think it would be crop !
Answer:
#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
double caffeineMg;
cin>>caffeineMg;
cout<<"After 6 hours: "<<fixed<<setprecision(2)<<caffeineMg/2.0<<" mg\n";
cout<<"After 12 hours: "<<fixed<<setprecision(2)<<caffeineMg/4.0<<" mg\n";
cout<<"After 24 hours: "<<fixed<<setprecision(2)<<caffeineMg/8.0<<" mg\n";
return 0;
}
Explanation:
- Declare a variable for caffeine and take the input from user.
- Print the results by dividing the caffeine by relevant Half Life.
- Use setprecision function to display the result up to 2 decimal places.
Technical writing is writing that is done for the purpose of educating, informing or directing someone on how to do something. Technical writing is significantly different than other types of writing such as narrative, because technical writing is intended to impart to the reader some specific skill or ability. Technical writing isn't for everyone. It is often very detail-oriented and usually involves writing within fields where some advanced knowledge is required. When given a technical writing assignment, it also must be approached in a certain way in order for you to be successful. but i would have to go with c- e commerce
