Write the Point Slope Form of the line of slope 5 and passing through the point (1, -1)

Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the g

Shtirlitz [24]

Answer:

The equation in the slope-intercept form is

y = -5x - 41

Step-by-step explanation:

The given equation in the question is;

y = -5x + 2

The equation of a straight line graph can be written in the form;

y = mx + c

where m is the slope and c is the intercept

From here, we can see that the slope m is -5

Since the line is parallel to the new line we are trying to write its equation, it means that they have the same value of intercept.

Hence, the slope of the new line is also -5

Now, we can write the equation of the new line as;

y = -5x + c

we need to get the value of c here however

To get the value of c, we need to input the value of x and y

From the graph, x = -7 and y = -6

Substituting these values, we have;

-6 = -5(-7) + c

-6 = 35 + c

c = -6 -35

c = -41

So the equation of the new line will be;

y = -5x - 41

7 0

3 years ago

Twice a number is less than 15 (turn into inequality)

velikii [3]

$x \times 2$

3 0

3 years ago

calculates the sum of the first 8 terms of an arithmetic progression starting with 3/5 and ending with 1/4

N76 [4]

We conclude that the sum of the first 8 terms of the arithmetic sequence is 17/5.

<h3>How to get the sum of the first 8 terms?</h3>

In an arithmetic sequence, the difference between any two consecutive terms is a constant.

Here we know that:

$a_1 = 3/5\\a_8 = 1/4$

There are 7 times the common difference between these two values, so if d is the common difference:

$a_1 + 7*d = a_8\\\\3/5 + 7*d = 1/4\\\\7*d = 1/4 - 3/5 = (5 - 12)/20 = -7/20\\\\d = -1/20$

Then the sum of the first 8 terms is given by:

$3/5 + (3/5 - 1/20) + (3/5 - 2/20) + ... + (3/5 - 7/20)\\\\8*(3/5) - (1/20)*(1 + 2 + 3+ 4 + 5 + 6 + 7) = 3.4 = 34/10 = 17/5$

So we conclude that the sum of the first 8 terms of the arithmetic sequence is 17/5.

If you want to learn more about arithmetic sequences:

brainly.com/question/6561461

#SPJ1

6 0

2 years ago

in the circl below, AD is diameter and AB is tangent at A. Suppose mADC=228*, find the measures of mCAB and mCAD. Type your nume

Andrew [12]

Given:

AD is diameter of the circle, AB is the tangent, and measure of arc ADC is 228 degrees.

To find:

The $m\angle CAB$ and $m\angle CAD$ .

Solution:

AD is diameter of the circle. So, the measure of arc AD is 180 degrees.

$m(arcADC)=m(arcAD)+m(arcDC)$

$228^\circ=180^\circ+m(arcDC)$

$228^\circ-180^\circ+=m(arcDC)$

$48^\circ+=m(arcDC)$

The measure inscribed angle is half of the corresponding subtended arc.

$m\angle CAD=\dfrac{1}{2}\times m(arcDC)$

$m\angle CAD=\dfrac{1}{2}\times 48^\circ$

$m\angle CAD=24^\circ$

AB is the tangent. So, $m\angle BAD=90^\circ$ because radius is perpendicular on the tangent and the point of tangency.

$m\angle BAD=m\angle CAB+m\angle CAD$

$90^\circ=m\angle CAB+24^\circ$

$90^\circ -24^\circ=m\angle CAB$

$66^\circ=m\angle CAB$

Therefore, $m\angle CAB=66^\circ$ and $m\angle CAD=24^\circ$ .

4 0

3 years ago

I NEED HELP THIS IS DUE ASAP

UNO [17]

Answer:

Proportional

Unproportional

Step-by-step explanation:

85 -6 = 79

79 -6 = 73

73 -6 = 67

1.49 +10 = 1.59

1.59 + 30 = 1.89

6 0

3 years ago

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Write the Point Slope Form of the line of slope 5 and passing through the point (1, -1)​

Write the Point Slope Form of the line of slope 5 and passing through the point (1, -1)