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vazorg [7]
2 years ago
11

Students measuring the mass of a substance record 1.127 g, 1.214 g, 1.304 g, and 1.184 g. Which other measurement of the substan

ce's mass would be most precise?  A. 1.514 g  B. 1.205 g  C. 1.416 g  D. 1.384 g
Chemistry
1 answer:
pickupchik [31]2 years ago
4 0

Answer:1.205g

Explanation:

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Answer:

some of them not believe in God

6 0
3 years ago
Consider the following chemical reaction:
jolli1 [7]

From the calculation, the moles of water produced is 18 moles of water.

<h3>What is a decomposition reaction?</h3>

A decomposition reaction is one in which a substance is split up into smaller parts.

We have the reaction; 2 Cr(OH)3(aq) ------------> Cr2O3(s) + 3H2O(l)

From this reaction;

2 moles of  Cr(OH)3 produced 3 moles of water

12 moles of  Cr(OH)3 will produce;

12 moles  *  3 moles / 2moles

= 18 moles of water

Hence, 12 moles of chromium (III) hydroxide produces 18 moles of water.

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4 0
1 year ago
What is the name of the compound (NH4)2SO4
GREYUIT [131]
The answer is Ammonium sulfate
3 0
3 years ago
On the basis of the information above, a buffer with a pH = 9 can best be made by using
telo118 [61]

Answer:

D H2PO4– + HPO42–

Explanation:

The acid dissociation constant for \mathbf{H_3PO_4 , H_2PO^{-}_4 ,  HPO_4^{2-}} are \mathbf{7\times 10^{-3}, \ \ 8\times 10^{-8} ,\ \  5\times 10^{-13}} respectively.

\mathbf{pka (H_3PO_4) = -log (7\times 10^{-3} )=2.2}

\mathbf{pka (H_2PO_4^-) = -log (8\times 10^{-8} )=7.1}

\mathbf{pka (HPO_4^{2-}) = -log (5\times 10^{-13} )=12.3}

The reason while option D is the best answer is that, the value of pKa for both

\mathbf{H_2PO^{-}_4 ,\  \& \  HPO_4^{2-}} lies on either side of the desired pH of the buffer. This implies that one is slightly over and the other is slightly under.

Using Henderson-Hasselbach equation:

\mathbf{pH = pKa + log \Big( \dfrac{HPO_4^{2-}}{H_2PO_4^-} \Big)}

3 0
2 years ago
How many valence electrons are in the element copernicium?<br><br><br> Will GIVE BRainLYEsT!!!!!
Ivahew [28]
As it is located at 7s ^2 it will have 2 valence electrons that due to its position in the s orbital it will be prone to losing them to obtain a noble gas configuration.
3 0
3 years ago
Read 2 more answers
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