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vazorg [7]
3 years ago
11

Students measuring the mass of a substance record 1.127 g, 1.214 g, 1.304 g, and 1.184 g. Which other measurement of the substan

ce's mass would be most precise?  A. 1.514 g  B. 1.205 g  C. 1.416 g  D. 1.384 g
Chemistry
1 answer:
pickupchik [31]3 years ago
4 0

Answer:1.205g

Explanation:

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Describe the method to make pure, dry crystals of magnesium sulfate from a metal oxide and dilute acid.
emmasim [6.3K]

Answer:

H2SO4(aq) + MgO(s) → H2O(l) + MgSO4(aq)

Explanation:

We must recall that the oxides of metals are bases. These metal oxides can react with dilute acids to yield salt and water.

Bearing that in mind, we want to obtain magnesium sulfate from a metal oxide and dilute acid.

In this case we need magnesium oxide and dilute sulphuric acid. The reaction occurs as follows;

H2SO4(aq) + MgO(s) → H2O(l) + MgSO4(aq)

6 0
3 years ago
Which part of the plant carries water and food to and from the leaves?
Alex777 [14]

Answer:

the stem, but if its more specific xylem cells

6 0
3 years ago
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The breaking buffer that we use this week contains 10mM Tris, pH 8.0, 150mM NaCl. The elution buffer is breaking buffer that als
olasank [31]

Answer:

A breakdown of the breaking buffer was first listed with its respective component and their corresponding value; then a table was made for the stock concentrations in which the volume that is being added was determined by using the formula M_1*V_1 = M_2*V_2. It was the addition of these volumes altogether that make up the 0.25 L (i.e 250 mL)  with water

Explanation:

Given data includes:

Tris= 10mM

pH = 8.0

NaCl = 150 mM

Imidazole = 300 mM

In order to make 0.25 L solution buffer ; i.e (250 mL); we have the following component.

Stock Concentration             Volume to be             Final Concentration

                                               added            

1 M Tris                                     2.5 mL                         10 mM

5 M NaCl                                  7.5 mL                        150 mM

1 M Imidazole                           75 mL                         300 mM    

M_1*V_1 = M_2*V_2. is the formula that is used to determine the corresponding volume that is added for each stock concentration

The stock concentration of Tris ( 1 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.01 M *250mL\\V_1 = 2.5mL

The stock concentration of NaCl (5 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.15 M *250mL\\V_1 = 7.5mL

The stock concentration of Imidazole (1 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.03 M *250mL\\V_1 = 75mL

Hence, it is the addition of all the volumes altogether that make up 0.25L (i.e 250 mL) with water.

5 0
3 years ago
A substance is melting, so it is transitioning from solid to liquid. What kind of change is this?
Nostrana [21]

Answer:

chemical or physical i dont know for sure i kniw i have learned this juat cant rember

8 0
4 years ago
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Copper has a density of 8.96 g/cm3. If 75.0 g of copper is added to 50.0 mL of water in a graduated cylinder, to what volume rea
Tcecarenko [31]

Answer:

The answer to your question is    Final volume = 58.37 ml

Explanation:

Data

density = 8.96 g/cm³

mass = 75 g

volume of water = 50 ml

Process

1.- Calculate the volume of copper

  Density = mass / volume

Solve for volume

  Volume = mass / density

Substitution

  Volume = 75/8.96

Simplification

  Volume = 8.37cm³    or 8.37 cm³

2.- Calculate the new volume of water in the graduated cylinder

  Final volume = 50 + 8.37

  Final volume = 58.37 ml

3 0
3 years ago
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