Answer:
When a wave is present in a medium (that is, when there is a disturbance moving through a medium), the individual particles of the medium are only temporarily displaced from their rest position.
Explanation:
Answer:
1.The substance(s) to the left of the arrow in a chemical equation are called reactants. A reactant is a substance that is present at the start of a chemical reaction. The substance(s) to the right of the arrow are called products . A product is a substance that is present at the end of a chemical reaction.The combustion of methane or octane is exothermic; it releases energy. CH4 + 2 O2 → CO2 + 2 H2O + energy The energies of the products are lower than the energiies of the reactants.
Explanation:
Answer:
Sample A is a pure substance
Sample B is a mixture
Explanation:
We are told that the when the yellow solid, sample A is ground it turned to orange colour and was then dissolved. Some part of the solid settled out at the bottom of the beaker while some part floated on top of the water. 50g of the solid was dissolved and 50.1g of the solid was recovered.
This implies that the substance is pure since the mass dissolved was almost the same mass recovered. The 0.1g addition in mass may result from incomplete drying of the solid.
For sample B, the distillation of the sample of density 0.77 g/ml left a fraction in the beaker with density 1.04 g/ml indicating that the substance is a mixture. Different components of a mixture possess different densities.
Answer:
b. The amount of SO3(g) decreases and the value for K increases.
Explanation:
Hello,
In this case, for the given reaction:

The change in the stoichiometric coefficient is:

In such a way, since the reagents have more moles than the products, based on Le Chatelier's principle, if the volume is increased, the side with more moles is favored. In addition, since the formation of reagent is favored, K is diminished based on the law of mass action shown below:
![K=\frac{[SO_3]_{eq}^2}{[SO_2]_{eq}^2[O_2]_{eq}}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BSO_3%5D_%7Beq%7D%5E2%7D%7B%5BSO_2%5D_%7Beq%7D%5E2%5BO_2%5D_%7Beq%7D%7D)
Therefore the answer is:
b. The amount of SO3(g) decreases and the value for K increases.
Best regards.
Answer:

Explanation:
Titration is a method used to determine the concentration of a substance. The formula for this is:

Where M is the molarity of the acid or base and V is the volume of the acid or base.
We know that 46.0 milliliters of a 0.15 molar solution of nitric acid wereused in the titration. 25.0 milliliters of solution of calcium hydroxide of unknown molarity were also used.

Substitute these known values into the formula.

We are solving for the molarity of the base, so we must isolate the variable
. It is being multiplied by 25.0 milliliters. The inverse operation of multiplication is division, so we divide both sides of the equation by 25.0 mL.


The units of milliliters (mL) cancel.



The original measurements have 2 or 3 significant figures. We always round our answer to the least number of sig figs, which is 2. For the number we calculated, that is the hundredths place. The 6 in the thousandths place tells us to round the 7 up to an 8.

The concentration of calcium hydroxide is approximately <u>0.28 M.</u>