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2 years ago

PLEASE HELP. I AM STRUGGLING.

Mathematics

1 answer:

Fittoniya [83]2 years ago

4 0

(1.25x8)1.06=18.55

1.325x + 8.48=18.55

1.325x = 10.07

$7.60

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1. a line with a slope of 1/3 passes through the point (3, 6) . which point also lies on this line?

valentina_108 [34]

1) Substituting into point-slope form, the equation of the line is y-6=⅓(x-3), which rearranges to:

y-6 = ⅓x - 1
y = ⅓x + 5

So, we can now substitute in the coordinates of each of the options to see which point lies on the line.

3 = ⅓(6) + 5 -> 3 = 7, which is false.
6 = ⅓(7) + 5 -> 6 = 22/3, which is false.
-3 = ⅓(-3) + 5 -> -3 = 4, which is false.
3 = ⅓(-6) + 5 -> 3 = 3, which is true.

So, the answer is (4) (-6, 3)

2) Substituting into point-slope form, the equation of the line is y - 5 = ¾(x-2), which rearranges to:

y - 5 = 0.75x - 1.5
y = 0.75x + 3.5

So, we can now substitute in the coordinates of each of the options to see which point lies on the line.

8 = 0.75(6)+3.5 -> 8 = 8, which is true.
9 = 0.75(5) + 3.5 -> 9 = 7.25, which is false.
1 = 0.75(-1) + 3.5 -> 1 = 2.75, which is false.
2 = 0.75(6) + 3.5 -> 2 = 8, which is false.

So, the answer is (1) (6, 8).

3 0

1 year ago

3. A drone takes off from the base of a mountain at a height of 27 ft below sea level. The drone

Korolek [52]

Answer:

669ft high

Step-by-step explanation:

642+27=669ft

5 0

3 years ago

A police cruiser is traveling at 20.0 m/s when the officer spies a speeder. The cruiser accelerates at 3.0 m/s^2 for 5.0 seconds

Tema [17]

For the first 5.0 seconds, the cruiser covers a distance of

$\left(20.0\dfrac{\rm m}{\rm s}\right)(5.0\,\mathrm s)+\dfrac12\left(3.0\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s)^2=137.5\,\mathrm m$

At this point, the cruiser will have achieved a velocity of

$\left(20.0\dfrac{\rm m}{\rm s}\right)+\left(3.0\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s)=35\dfrac{\rm m}{\rm s}$

The cruiser will take

$\left(35\dfrac{\rm m}{\rm s}\right)-\left(5.0\dfrac{\rm m}{\mathrm s^2}\right)t=0\implies t=7.0\,\mathrm s$

to come to a stop as it decelerates. It will have covered a total distance of

$(137.5\,\mathrm m)+\left(35\dfrac{\rm m}{\rm s}\right)(7.0\,\mathrm s)+\dfrac12\left(-5.0\dfrac{\rm m}{\mathrm s^2}\right)(7.0\,\mathrm s)^2=\boxed{260\,\mathrm m}$

8 0

2 years ago

Can someone please help me with this square root problem?

nadya68 [22]

Answer:

x=14.87

Step-by-step explanation:

What we want to use is pythagoras theorem:

a^2+b^2=c^2, where c is the hypotenuse

10^2+11^2=x^2

221=x^2

x= $\sqrt{221}$

x=14.866...

x=14.87

4 0

2 years ago

A wire that is 22 feet long connects the top of a pole to the ground. The wire is attached to the ground at a point that is 10 f

krok68 [10]

✰ Concept Used :-

⠀

In this question, we can clearly observer that the diagram shows a right angled triangle. And, we have been provided with the value of base, and the value of hypotenuse, using the pythagoras theorem, now we can easily find out the value of the perpendicular i.e. the value of the side h. According to the pythagoras theorem, square of hypotenuse is equal to the sum of square of perpendicular and square of side respectively. Therefore, square of side is equal to the difference of square of hypotenuse and square of perpendicular.

⠀

✰ Given Information :-

⠀

Hypotenuse = 22 ft.
Base = 10 ft.

⠀

✰ To Find :-

⠀

The value of side or the perpendicular

⠀

✰ Formula Used :-

⠀

$\star \: \underline{ \boxed{ \purple { \sf {Side}^{2} = {Hypotenuse}^{2} - {Base}^{2} }}} \: \star$

⠀

✰ Solution :-

⠀

$\sf \longrightarrow {Side}^{2} = {(22 \: ft)}^{2} - {(10 \: ft)}^{2} \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{2} = {484 \: ft}^{2} - {100 \: ft}^{2} \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{2} = {384 \: ft}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{} = \sqrt{ {384 \: ft}^{2} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{} = \underline{ \boxed{ \frak{ \green{19.60 \: ft}}}} \: \star \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\$

Thus, option B. 19.60 ft. is the correct option.

⠀

$\underline{\rule{230pt}{2pt}} \\ \\$

4 0

2 years ago