Let us formulate the independent equation that represents the problem. We let x be the cost for adult tickets and y be the cost for children tickets. All of the sales should equal to $20. Since each adult costs $4 and each child costs $2, the equation should be
4x + 2y = 20
There are two unknown but only one independent equation. We cannot solve an exact solution for this. One way to solve this is to state all the possibilities. Let's start by assigning values of x. The least value of x possible is 0. This is when no adults but only children bought the tickets.
When x=0,
4(0) + 2y = 20
y = 10
When x=1,
4(1) + 2y = 20
y = 8
When x=2,
4(2) + 2y = 20
y = 6
When x=3,
4(3) + 2y= 20
y = 4
When x = 4,
4(4) + 2y = 20
y = 2
When x = 5,
4(5) + 2y = 20
y = 0
When x = 6,
4(6) + 2y = 20
y = -2
A negative value for y is impossible. Therefore, the list of possible combination ends at x =5. To summarize, the combinations of adults and children tickets sold is tabulated below:
Number of adult tickets Number of children tickets
0 10
1 8
2 6
3 4
4 2
5 0
The complete question in the attached figure
we know that
t<span>he centroid is always 2/3 the distance of each median to each vertex
TW=30
TW=TY+YW
TY=(2/3)*30---------> TY=20
then
YW=TW-TY-----------> YW=30-20-----------> YW=10
the answer is
YW=10</span>
53 3/4=53.75
To find out how many 4ft ropes you can make divide 53.75 by 4
53.75/4=13.4375
You can make 13 4ft ropes out of a 53.75ft rope
Answer:
I would say 15 batteries because you were gonna need five batteries but then you extend it to nine days.
Step-by-step explanation:
Answer:
x+8=3x
Step-by-step explanation:
4x=20
4x/4=20/4
x=5
The solution to the first equation is x=5.
x/2=8
2(x/2)=2(8)
x=16
The solution to the second equation is x=16.
x+8=3x
x+8-x=3x-x
8=2x
8/2=2x/2
x=4
The solution to the third equation is x=4.
x=x+5/2
x-x=x+5/2-x
-x=5/2
x=-5/2
The solution to the fourth equation is x=-5/2.
The equation x+8=3x has the solution to x=4.
