N= 7.01 :D I’m pretty sure that’s the answer :)
Answer:
E
Step-by-step explanation:
Solution:-
- We are to investigate the confidence interval of 95% for the population mean of walking times from Fretwell Building to the college of education building.
- The survey team took a sample of size n = 24 students and obtained the following results:
Sample mean ( x^ ) = 12.3 mins
Sample standard deviation ( s ) = 3.2 mins
- The sample taken was random and independent. We can assume normality of the sample.
- First we compute the critical value for the statistics.
- The z-distribution is a function of two inputs as follows:
- Significance Level ( α / 2 ) = ( 1 - CI ) / 2 = 0.05/2 = 0.025
Compute: z-critical = z_0.025 = +/- 1.96
- The confidence interval for the population mean ( u ) of walking times is given below:
[ x^ - z-critical*s / √n , x^ + z-critical*s / √n ]
Answer: [ 12.3 - 1.96*3.2 / √24 , 12.3 + 1.96*3.2 / √24 ]
Answer:
LM = 14
Step-by-step explanation:
LM = AC/2
LM = 28/2
<u>LM = 14</u>
Hope this helps!
The perpendicular bisector of the segment passes through the midpoint of this segment. Thus, we will initially find the midpoint P:
Now, we will calculate the slope of the segment support line (r). After this, we will use the fact that the perpendicular bisector (p) is perpendicular to r:
We can calculate the equation of
p by using its slope and its point P:
Take logs of both sides:-
ln 625^x = ln 5
x * ln 0.625 = ln 5
x = ln 5 / ln 625
x = 0.25 answer
