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2 years ago

Create a polynomial that has 10 roots.

Mathematics

1 answer:

Colt1911 [192]2 years ago

7 0

Answer:

(x – 3)(x + 5)(x + ½) = (x2 + 2x – 15)(x + ½) = x3 + 2.5x2 – 14x – 7.5

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Please Factor: <br> 900 - 1 =

timama [110]

The factoriztion of 900-1= 29,31

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3 years ago

Suppose you deposit $2,000 in a savings account that pays interest at an annual rate of

Veronika [31]

C because it showing the contain of 2,500

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3 years ago

Let a and b be roots of x² - 4x + 2 = 0. find the value of a/b² +b/a²

erastovalidia [21]

Answer:

$\dfrac{a}{b^2}+\dfrac{b}{a^2}=10$

Step-by-step explanation:

Given equation: $x^2-4x+2=0$

The roots of the given quadratic equation are the values of x when $y=0$ .

To find the roots, use the quadratic formula:

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=1, \quad b=-4, \quad c=2$

$\begin{aligned}\implies x & =\dfrac{-(-4) \pm \sqrt{(-4)^2-4(1)(2)}}{2(1)}\\& =\dfrac{4 \pm \sqrt{8}}{2}\\& =\dfrac{4 \pm 2\sqrt{2}}{2}\\& =2 \pm \sqrt{2}\end{aligned}$

$\textsf{Let }a=2+\sqrt{2}$

$\textsf{Let }b=2-\sqrt{2}$

Therefore:

$\begin{aligned}\implies \dfrac{a}{b^2}+\dfrac{b}{a^2} & = \dfrac{2+\sqrt{2}}{(2-\sqrt{2})^2}+\dfrac{2-\sqrt{2}}{(2+\sqrt{2})^2}\\\\& = \dfrac{2+\sqrt{2}}{6-4\sqrt{2}}+\dfrac{2-\sqrt{2}}{6+4\sqrt{2}}\\\\& = \dfrac{(2+\sqrt{2})(6+4\sqrt{2})+(2-\sqrt{2})(6-4\sqrt{2})}{(6-4\sqrt{2})(6+4\sqrt{2})}\\\\& = \dfrac{12+8\sqrt{2}+6\sqrt{2}+8+12-8\sqrt{2}-6\sqrt{2}+8}{36+24\sqrt{2}-24\sqrt{2}-32}\\\\& = \dfrac{40}{4}\\\\& = 10\end{aligned}$

6 0

1 year ago

Read 2 more answers

When I graphed the linear function, it turned out to be a wavy curve.

Elden [556K]

Answer:

B. The statement does not make sense because a linear function has a straight-line graph.

Step-by-step explanation:

Linear functions have a general form y = m*x +b and only yield straight-line graphs. Therefore, the statement does not make sense, either the graphed function is not linear, or there was an error in the graphing process. The answer is alternative B.

*Note that alternative D is wrong because it is incomplete, since linear functions can have a rate of change that increases (m > 0), decreases (m < 0) or that is zero (m = 0).

4 0

3 years ago

What are the ways to represent the solution of inequality 5(x+2)>7x+2(x-1)

bekas [8.4K]

1. multiply 5 inside of the parenthesis
5x+10
2. multiply the 2 inside the parenthesis and add the variables
9x-2

6 0

2 years ago