Find the line that is normal to the parabola at the given point
remember that normal means perpendicular
perpendicular lines have slopes that multiply to -1
we can use point slope form to write the equation of the line since we are given the point (1,0)
we just need the slope
take derivitive
y'=1-2x
at x=1
y'=1-2(1)
y'=1-2
y'=-1
the slope is -1
the perpendicular of that slope is what number we can multiply to get -1
-1 times what=-1?
what=1
duh
so
point (1,0) and slope 1
y-0=1(x-1)
y=x-1 is da equation
solve for where y=x-1 and y=x-x² intersect
set equatl to each other since equal y
x-1=x-x²
x²-1=0
factor difference of 2 perfect squares
(x-1)(x+1)=0
set to zero
x-1=0
x=1
we got this point already
x+1=0
x=-1
sub back
y=-1-(-1)²
y=-1-(1)
y=-1-1
y=-2
it intersects at (-1,-2)
Answer: 3
Step-by-step explanation:
D they all have the same slope.
The expression that models the length of the second leg of the triangle is <u>2x - 3.</u>
<u><em>Recall</em></u>:
The area of a triangle = 
<em><u>Given</u></em>:
Area of triangle = 
Length of one of the legs = 3x + 1
Therefore, it means that multiplying both legs should give us:
To find the expression that models the other leg, divide by 3x + 1:
Therefore, the expression that models the length of the second leg of the triangle is <u>2x - 3.</u>
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brainly.com/question/20712284
Answer:
4
Step-by-step explanation:
