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2 years ago

How to find the value of x in degrees HELP

Mathematics

1 answer:

Marta_Voda [28]2 years ago

7 0

Answer: X= 16

Step-by-step explanation:

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If 2 - 2 is a factor of 2.? - bx - 10, what is the value of b?

aleksandr82 [10.1K]

Bajanhxhsjsjshsjsjshhshshshsheh

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2 years ago

Land's Bend sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the intern

Naya [18.7K]

Answer:

80% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases ( $\mu_1-\mu_2$ ) is [-9.132 , 23.332].

Step-by-step explanation:

We are given that a random sample of 7 sales receipts for mail-order sales results in a mean sale amount of $81.70 with a standard deviation of $18.75.

A random sample of 11 sales receipts for internet sales results in a mean sale amount of $74.60 with a standard deviation of $28.25.

Firstly, the Pivotal quantity for 80% confidence interval for the difference between population means is given by;

P.Q. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ~ $t__n__1-_n__2-2$

where, $\bar X_1$ = sample mean sales receipts for mail-order sales = $81.70

$\bar X_2$ = sample mean sales receipts for internet sales = $74.60

$s_1$ = sample standard deviation for mail-order sales = $18.75

$s_2$ = sample standard deviation for internet sales = $28.25

$n_1$ = size of sales receipts for mail-order sales = 7

$n_2$ = size of sales receipts for internet sales = 11

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2} +(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(7-1)\times 18.75^{2} +(11-1)\times 28.25^{2} }{7+11-2} }$ = 25.11

Here for constructing 80% confidence interval we have used Two-sample t test statistics as we don't know about population standard deviations.

So, 80% confidence interval for the difference between population means, ( $\mu_1-\mu_2$ ) is ;

P(-1.337 < $t_1_6$ < 1.337) = 0.80 {As the critical value of t at 16 degree

of freedom are -1.337 & 1.337 with P = 10%}

P(-1.337 < $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ < 1.337) = 0.80

P( $-1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ < ${(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}$ < $1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ) = 0.80

P( $(\bar X_1-\bar X_2)-1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ < ( $\mu_1-\mu_2$ ) < $(\bar X_1-\bar X_2)+1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ) = 0.80

80% confidence interval for ( $\mu_1-\mu_2$ ) =

[ $(\bar X_1-\bar X_2)-1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ , $(\bar X_1-\bar X_2)+1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ]

= [ $(81.70-74.60)-1.337 \times {25.11 \times \sqrt{\frac{1}{7} +\frac{1}{11} } }$ , $(81.70-74.60)+1.337 \times {25.11 \times \sqrt{\frac{1}{7} +\frac{1}{11} } }$ ]

= [-9.132 , 23.332]

Therefore, 80% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases ( $\mu_1-\mu_2$ ) is [-9.132 , 23.332].

4 0

3 years ago

Carlos buys a phone that cost $250. He pays a monthly rate of $75. What is the independent variable of this function ?

erastova [34]

Answer: 250+75x

Step-by-step explanation: 250 is the flat charge on the phone, and he pays 75 dollars as a monthly rate. x represents the amount on months.

7 0

2 years ago

Anton is approved for overtime at his job. Last week he worked a total of 45 hours , how many hours of overtime did he work

pochemuha

Answer:

B. 5 Hours

Step-by-step explanation:

any work over 40 hours in a 168 hour period is counted as overtime. So take 45 (his total) and subtract it by 40 and you get 5. 45 - 40 = 5 hours.

8 0

3 years ago

Drag the expressions to the table to show whether the product is less than 3/4, greater than 3/4, or equal to 3/4.

KiRa [710]

A fraction 3/4 is called greater than 3/4 if,

Numerator > denominator,

Otherwise it is less than 3/4 ,

$\frac{1}{3} \times \frac{3}{4}=\frac{1}{4}$

$\begin{aligned}&\frac{5}{2} \times \frac{3}{4}=\frac{15}{8} \\&\because 8 < 15 \\&\Longrightarrow \frac{5}{2}\times \frac{3}{4} < 3/4 \\&\frac{7}{7} \times \frac{3}{4}=\frac{3}{4} \\&\because 3 < 4 \\&\Longrightarrow \frac{3}{4} \times \frac{3}{4} = 1 \\& \frac{9}{7} \times \frac{3}{4}=\frac{27}{28} \\&\because 28 > 27 \\&\Longrightarrow \frac{5}{5} \times \frac{3}{4} > \frac{3}{4} \end{aligned}$

A fraction represents a portion of a total. This entire may refer to a place or a group of places. The Latin word "fraction," which meaning "to break," is the source of the English term "fraction." The distribution of food and supplies as well as the lack of a metal currency were among the mathematical issues that the Egyptians utilized fractions to solve because they were the first civilization to understand fractions.

Only verbal descriptions of a portion of the whole were used to write fractions in ancient Rome. The numerator and denominator of fractions were first written in India with one number above the other, but without a line. The line used to divide the numerator and the denominator was only added by Arabs.

To learn more about fraction brainly.com/question/10354322

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1 year ago