Answer:
9
Step-by-step explanation:
This means that 9/(9+72)=(3x-20)/(3x+36), or 1/9=(3x-20)/(3x+36). Cross-multiply to get that 27x-180=3x+36, so 24x=216, and x=9.
Answer:
Step-by-step explanation:
Let's look at the first two, and hopefully you'll be able to figure the rest out:
1. Answer below
![d = rt](https://tex.z-dn.net/?f=d%20%3D%20rt)
The problem asks us to solve for
, so that means we need to get
on one side of the equation by itself. To do so, we will need to divide both sides of the equation by
:
![\frac{d}{t} = \frac{rt}{t}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bt%7D%20%3D%20%5Cfrac%7Brt%7D%7Bt%7D)
![\frac{d}{t} = r](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bt%7D%20%3D%20r)
2. Answer below
![B = T - Lc](https://tex.z-dn.net/?f=B%20%3D%20T%20-%20Lc)
The problem asks us to solve for
, so that means we need to get
on one side of the equation by itself. To do so, we will need to add
to both sides of equation:
![B + Lc = T - Lc + Lc](https://tex.z-dn.net/?f=B%20%2B%20Lc%20%3D%20T%20-%20Lc%20%2B%20Lc)
![B + Lc = T](https://tex.z-dn.net/?f=B%20%2B%20Lc%20%3D%20T)
<span>Winning Probablity = 0.2, hence Losing Probability = 0.8
Probablity of winning atmost one time, that means win one and lose four times or lose all the times. So p(W1 or W0) = p (W1) + p(W0)
Winning once W1 is equal to L4, winning zero times is losing 5 times.
p(W1) = p(W1&L4) and this happens 5 times; p(W0) = p(L5);
p (W1) + p(W0) = p(L4) + p(L5)
p(L4) + p(L5) = (5 x 0.2 x 0.8^4) + (0.8^5) => 0.8^4 + 0.8^5
p(W1 or W0) = 0.4096 + 0.32768 = 0.7373</span>
You can represent this problem by using the multiplication problem 5x4