Expand the expression as
(<em>s</em> + 1)³/<em>s</em> ⁵ = (<em>s</em> ³ + 3<em>s</em> ² + 3<em>s</em> + 1)/<em>s</em> ⁵
… = 1/<em>s</em> ² + 3/<em>s</em> ³ + 3/<em>s</em> ⁴ + 1/<em>s</em> ⁵
Then taking the inverse transform, you get
LT⁻¹ [1/<em>s</em> ² + 3/<em>s</em> ³ + 3/<em>s</em> ⁴ + 1/<em>s</em> ⁵]
… = LT⁻¹ [1/<em>s</em> ²] + LT⁻¹ [3/<em>s</em> ³] + LT⁻¹ [3/<em>s</em> ⁴] + LT⁻¹ [1/<em>s</em> ⁵]
… = LT⁻¹ [1!/<em>s</em> ²] + 3/2 LT⁻¹ [2!/<em>s</em> ³] + 1/2 LT⁻¹ [3!/<em>s</em> ⁴] + 1/24 LT⁻¹ [4!/<em>s</em> ⁵]
… = <em>t</em> + 3/2 <em>t</em> ² + 1/2 <em>t</em> ³ + 1/24 <em>t</em> ⁴
Selection C is appropriate.
_____
A. The population is constant at 8.
B. The population is constant at 24.
C. Matches the problem description.
D. The initial population is 24 and after 1 hour is 72.
2 is in the hundred thousands place
Even function is symmetrical about the y axis
not sure what it means if the polynomial is positive
the zeroes are how many times it hits the x axis
it hits 4 times so 4 zeros
She can make 3 since theres only 3 mascaras? and for each makeup kit she can add two eyeshadows and one mascara