By solving given equations, the value of c is 30.
Given two equations
x + 2y = 10 and
3x + 6y = c
These lines represents the same line for some constant c.
Value of c:
x + 2y = 10-------------(1)
3x + 6y = c-------------(2)
Dividing equation (2) by 3
After solving the above equation, we get
x + 2y = c/3-----------(3)
Remember that a line is written as ax + by = c, in our case, both lines have a =1 and b = 2. Therefore, in orther that the two lines are equal, we need that, 10 = c/3
c = 10 × 3 = 30
c = 30
Therefore,
The value of c is 30.
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Answer:
Step-by-step explanation:
Since we're looking at perpendicular lines, the slope of the new line is the reciprocal of the original line.
So the slope of our new line is 
So far, we are looking at 
Now we need to find the b value by plugging in the given point.
So the final equation is
Answer:
The discount% is 15%
Step-by-step explanation:
Given : The price of a sweater was slashed from Rs 960 to Rs 816 by a shopkeeper in the winter season.
To find : The rate of discount given by him?
Solution :
According to question,
The market price of the sweater is Rs.960
The selling price of the sweater is Rs.816
The discount on the sweater is given bY
Discount % is given by
Therefore, The discount% is 15%.
Answer:
1.) 12000
2.) 6750
3.) 2.41
Step-by-step explanation:
Given the Equation :
f(t)=12,000(3/4)^t. ; where, t = time ; f(t) = worth of car at time, t
When, car was purchased, t = 0
t = 0
f(0) = 12000(3/4)^0
= 12000 * 1
= 12000
2.)
f(2) ; this mean the worth of the car after 2 years :
f(2)=12,000(3/4)^t.
12000(3/4)^2
12000 * 0.5625
= 6750
When car will be worth 6000
f(t) = 6000
f(t)=12,000(3/4)^t.
6000 = 12,000(3/4)^t
6000 / 12000 = (3/4)^t
1/2 = (3/4)^t
Take the log of both sides :
Log(0.5) = log(0.75)^t
log(0.5) = tlog(0.75)
- 0.301029 = - 0.124938t
t = - 0.301029 / - 0.124938
t = 2.4094
t = 2.41 years
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