Question

A cylindrical water tank has a diameter of 9 feet and a height of 16 feet. Each can of paint covers 50 square feet. What is the minimum number of cans of paint needed to cover the outside of the tank

Answer 1

Answer:

12 cans

Step-by-step explanation:

The area of the outside of the tank:

radio = half diameter = 4.5 ft.

base: $A_{b} =\pi r^{2} =\pi (4.5)^{2} =20.25\pi$

Top: = base $=20.25\pi$

cylinder: $2\pi rh=2\pi (4.5)(16)=144\pi$

Total area to paint: $144\pi +2(20.25\pi) =184.5\pi =579.6sq.ft.$

Number of cans of paint:

$c=\frac{579.6}{50} =11.59=12$

Hope this helps