A = LW
W = L + 6
A = 160
160 = L(L + 6)
160 = L^2 + 6L
L^2 + 6L - 160 = 0
(L + 16)(L - 10) = 0
L + 16 = 0
L = -16 (extraneous solution...not ur answer)
L - 10 = 0
L = 10 <====the length (L) = 10 yds
W = L + 6
W = 10 + 6
W = 16 < ==== width (W) = 16 yds
Since angles EFA, AFB, and BFC lie on a straight line, then they must add up to 180° (angle sum of a straight line)
So, 7x + 4 + 8x + 6 + 6x + 2 = 180
21x + 12 = 180
21x = 168
x = 8
Answer:
If the graphs of the equations intersect, then there is one solution that is true for both equations.
Step-by-step explanation:
