<u>Virus outbreaks in an organization:</u>
In an organization end user who uses the computer or laptop or workstation is not aware of virus outbreaks. So As IT administrator of an organization she/he has aware of latest virus attack and rectification solution before outbreaks.
Common causes for this virus outbreaks problem is update virus definition or database. Update operating system patches on regular basis.
Installation appropriate anti-virus in each workstation or desktop or laptop and scheduling virus scanning and take necessary steps.
To address and troubleshoot disconnect workstation and desktop or laptop from LAN. Uninstalled unnecessary software, delete temp folder contents.
Answer:
World at least 1 percent
Explanation:
Cybercrime are crimes that focuses on networks of computers whereby a computer is used to commit the crime or a computer is the target of the crime, with the possible effect of a threat to the security and financial wellbeing of a person, an establishment or country
According to the report by Zhanna Malekos Smith and Eugenia Lostri, 'The Hidden Costs of Cybercrime' the monetary cost of cybercrime which is estimated at $945 billion is <u>a little above 1% of the World's GDP</u> which is around $87.55 trillion.
Credit risk, liquidity risk, asset-backed risk, foreign investment risk, equity risk and currency risk
Answer:
In general, a scientific law is the description of an observed phenomenon. It doesn't explain why the phenomenon exists or what causes it. The explanation of a phenomenon is called a scientific theory. It is a misconception that theories turn into laws with enough research.
Explanation:
Explanation:
Step one
The maximum size of data field in each fragment = 480
(because there are 20 bytes IP header) Thus the number of required
fragments 
thus the number of required fragment is 4
Step two
Each fragment will have identification number 291. each fragment except the last one will be of size 500 bytes (including IP header). the offset of the fragments will be 0, 60, 120, 180. each of the first 3 fragments will have
flag = 1; the last fragment will have flag =0
