Answer:
Explanation:
If L(D1) = L(D2), the D has every state being final
If L(D1) = L¯(D2), the D has every state being final
If L(D1) = ∅, then L(D) = L(D2).
If L(D1)=Σ, L(D) = L(D2)
Answer:
The code is not dereferencing the pointers. You have to place an asterisk in front of the pointer to read the value the pointer points to.
Explanation:
So "if (str1 != str2)" must be "if (*str1 != *str2)".
likewise:
while (*str1 != 0 && *str2 != 0)
and
result = (*str1 == *str2);
let's say they catch-up to each other after t hour.
so
in t hour distance travelled by Renee
d = speed × time = 50t
in t hour distance travelled by Kim
d = speed × time = 60(t-1) + 0×1 = 60(t-1)
Note: here kim didn't covered any distance in first hour and in rest t-1 hour it travelled all distance
now.as distance travelled by both is same so
60(t-1) = 50t
60t -60 = 50t
adding 60 both sides
60t = 50t+60
subtracting 50t both sides
60t -50t = 50t+60 - 50t
10t = 60
dividing by 10 both sides
t = 60/10 = 6
so in 6 hour both will catch-up to each other
