Answer:
designing the computer network
Explanation:
Answer:
Option B i.e.,802.11ac is the correct option.
Explanation:
Because 802.11ac is that standard that is selected by the technician to install that router which is wireless and that router has the fastest speed of the data transfering that is 5GHz frequency. Mostly, the following standard is used in the large organizations by which the work done on time without any restriction to access the internet. So, that's why the following option is correct.
Answer:
True
Explanation:
I just know the answer because I'm a genius hehe
Answer:
Looking up the answer on google works but in my experience if you put the whole question onto brainly then look for the one with the best stars and most then the answer will be correct, thats how i have 100% on all my assingments, sorry if this isnt the answer you wanted but it helps
Explanation:
Answer:
Verbatim Identifier
Explanation:
- Verbatim Identifier contains @ symbol as a prefix by which enables you to use reserved words of a programming language as identifier. For example the keywords like int, double, goto, char, else, while, for, float etc can be used as strings or variable names if @ symbol is added before these words e.g. @char, @while, @void, @int etc.
- The compiler of a language will recognize such identifiers as verbatim identifiers and compiles them without giving an error that these are reserved words.
- Verbatim identifier is used for program that is written in other languages and those languages don't have same reserved words.
- For example: cout<<"use of verbatim identifier";<<@for; In this statement, for keyword which is used in for loop can be used as an identifier with @ in the prefix.
- The escape sequences if used with @ symbol in prefix then they are interpreted in a different way. For example in C#
string a = "\\C:\torrent\new\file";
Console.WriteLine(a);
This statement will give the following output:
\C: orrent
ewfile
This means that the \t in the start of torrent and \n in the start of new word is taken as an escape sequence and output displayed is giving tab space because of \t and prints the rest of the words in new line because of \n escape sequence.
Now lets use this with the @ symbol
string a = @"\\C:\torrent\new\file";
Console.WriteLine(a);
The output will now be:
\\C:\torrent\new\file
\t and \n are not taken as escape sequences by the compiler because of @ symbol.
