Step-by-step explanation:
Hope this helps you ☺️☺️☺️
Since the triangles are similar, then 32 = x+7 those two angles are too
solve for "x"
now using proportions
solve for JK
solve for KG
the scale factor of the perimeter of both triangles is just the same as the ratio of the sides, or
For Part A, what to do first is to equate the given equation to zero in order to find your x intercepts (zeroes)
0=-250n^2+3,250n-9,000 after factoring out, we get
-250(n-4)(n-9) and these are your zero values.
For Part B, you need to square the function from the general equation Ax^2+Bx+C=0. So to do that, we use the equated form of the equation 0=-250n^2+3,250n-9,000 and in order to have a positive value of 250n^2, we divide both sides by -1
250n^2-3,250n+9,000=0
to simplify, we divide it by 250 to get n^2-13n+36=0 or n^2-13n = -36 (this form is easier in order to complete the square, ax^2+bx=c)
in squaring, we need to apply <span><span><span>(<span>b/2</span>)^2 to both sides where our b is -13 so,
(-13/2)^2 is 169/4
so the equation now becomes n^2-13n+169/4 = 25/4 or to simplify, we apply the concept of a perfect square binomial, so the equation turns out like this
(n-13/2)^2 = 25/4 then to find the value of n, we apply the square root to both sides to obtain n-13/2 = 5/2 and n is 9. This gives us the confirmation from Part A.
For Part C, since the function is a binomial so the graph is a parabola. The axis of symmetry would be x=5.
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