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3 years ago

Graph to find the x-intercept for the equation y + 2 = 2(x + 3).

Mathematics

1 answer:

WINSTONCH [101]3 years ago

7 0

Answer:

The drop down answer is -2,0 and you'll want to graph -2,0 on the graph and place another point on 4,0

Step-by-step explanation:

Just did it on edge buddy

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PLS HELP! Tell whether each of the following is a function or not. How do you know?

Nataly [62]

Answer: It is

Step-by-step explanation:

None of the lines will ever touch each other resulting in a function.

7 0

3 years ago

Read 2 more answers

. -5, 10, 7, 10, 9, 0, 1, 9, -1, 5 Work out the mean.

bezimeni [28]

Answer:

Step-by-step explanation: because its online

4 0

3 years ago

You can do both problems if want

Agata [3.3K]

A= π r2 and v=3.14d

---Volume(v=3.14d):

3.14(15) equals 47.1

47.1 rounds to 47

nearest hundreth would be 0 that rounds to .1 or .10,which rounds to 47
v=47

---Area(π r2)

3.14(7.5)^2 is 3.14(56.25)
176.625

176.625 rounded to the nearest hundreth is 176.630.

Answer:

The area of a circle with the diameter of 15 is 176.630.

4 0

3 years ago

In rectangle abcd, points p and q lie on side AB and DC respectively. Angle PMQ is a right angle, M is the midpoint of side BC a

nirvana33 [79]

Answer:

PM:MQ = 8:3.

Step-by-step explanation:

$\rm \angle B\hat{M}P + 90^{\circ} + \angle C\hat{M}Q = 180^{\circ}$ ;

$\implies \rm \angle B\hat{M}P + \angle C\hat{M}Q = 90^{\circ}$ ;

$\implies \rm 90^{\circ} - \angle B\hat{M}P = \angle C\hat{M}Q$ .

Also,

$\rm \angle B\hat{P}M = 90^{\circ} - \angle B\hat{M}P$ in right triangle PBM.

Thus $\rm \angle{P\hat{B}M} = \angle C\hat{M}Q$ .

Additionally $\rm \angle \hat{B} = 90^{\circ} = \angle \hat{C}$ .

Therefore $\rm \triangle PBM \sim \triangle MCQ$ .

$\rm \displaystyle BC = 2\;MC$ for M is the midpoint of segment BC.

$\rm \displaystyle PB = \frac{4}{3}BC = \frac{8}{3}MC$ .

$\rm \triangle PBM \sim \triangle MCQ$ implies that

$\displaystyle \rm PM:MQ = PB:MC = 1:\frac{8}{3} = 8:3$ .

8 0

3 years ago

Please help with this ASAP!!1

d1i1m1o1n [39]

Answer:

a. OM is congruent to ON.

Step-by-step explanation:

To use the HL Theorem, you must have a congruent hypotenuse and a congruent leg. In this case, you have two congruent hypotenuses. You just need to find two congruent legs.

a. OM is congruent to ON. This says that two legs are congruent, so this is your answer.

b. LM is congruent to ML. This does not help as it is saying a segment is the same as the same segment.

c. and d. Both of these use angle measurements, which does not help with the HL Theorem.

Hope this helps!

7 0

3 years ago