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marshall27 [118]
3 years ago
7

ASAP HELP PLEASE WILL MARK BRAINLIST

Mathematics
2 answers:
inn [45]3 years ago
7 0
Substitute 3 for wherever m is. Answer is 4
Andrew [12]3 years ago
3 0
The answer is 4 i believe
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A cube has side length x. One side of the cube is increased by 4 inches, and another side is doubled. The volume of the new rect
AfilCa [17]

Let

x-------> the length side  of the original cube

we have

2x^{3} +8x=450\\2x^{3}=450-8x

Divide by 2 both sides

x^{3}=225-4x

The system of equations is equal to

y=x^{3} --------> equation 1

y=225-4x --------> equation 2

using a graphing tool

see the attached figure  

we know that

the solution of the system of equations is the intersection both graphs

therefore

the solution is

x=5.86\ in

therefore

<u>the answer is</u>

5.86\ inches


6 0
3 years ago
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Derive the equation of the parabola with a focus at (0, −4) and a directrix of y = 4.
CaHeK987 [17]

<u>Answer:</u>

y=-\frac{1}{16} x^2

<u>Step-by-step explanation:</u>

Equation of parabola with focus at (0,-4) and directrix is y=4.

We know that parabola is the locus of all the points such that the distance from fixed point on the parabola to fixed line directrix is the same.

The parabola is opening downwards.

Let any point on parabola is (x,y).

Distance from focus(0,-4) to (x,y) = \sqrt{(x-0)^2+(y-(-4))^2}=|y-4|

\sqrt{(x-0)^2+(y-+4)^2}=|y-4|

(x-0)^2+(y+4)^2=(y-4)^2

(x)^2+(y+4)^2=(y-4)^2

x^2+(y^2+4y+4y+16)=y^2-4y-4y+16

x^2+y^2+8y+16=y^2-8y+16

x^2+16y^2=0

16y=-x^2

y=-\frac{1}{16} x^2

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2 years ago
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\sin(t) =  \frac{1}{2} &#10;\\&#10;\\ \cos(t) = - \frac{ \sqrt{3} }{2} &#10;\\&#10;\\ \tan(t) =  \frac{\sin(t)}{\cos(t)}= - \frac{1}{ \sqrt{3} } &#10;\\&#10;\\ \csc(t) =  \frac{1}{\sin(t)}= 2 &#10;\\&#10;\\ \sec(t) =\frac{1}{\cos(t)}=- \frac{2}{ \sqrt{3}}  &#10;\\&#10;\\ \cot(t) = \frac{1}{\tan(t)}=- \sqrt{3}

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3 years ago
Find the length of a side and perimeter of square those area is 256 square​
exis [7]
You have to add the square root then do the division 54 is the answer
3 0
2 years ago
The diameter of this circle is 12 inches. The diameter of the smaller circle is 8 inches. find the area of the SHADED region.
kolezko [41]

Answer:

so you multiply 12 by 8 =96

3 0
3 years ago
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