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zaharov [31]
3 years ago
12

Plz answer the question thanks

Mathematics
2 answers:
Marina CMI [18]3 years ago
6 0

Answer:

this is the answer okkkkkkkkkkkkkkkk

lesantik [10]3 years ago
6 0

Answer:

81 and 324

Step-by-step explanation:

total units->3+12=15

1u=405÷15=27

3u=27×3=81

12u=27×12=324

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The image of a parabolic lens is projected onto a graph. The image crosses the x-axis at –2 and 3. The point (–1, 2) is also on
timofeeve [1]

Given:

The image of a lens crosses the x-axis at –2 and 3.

The point (–1, 2) is also on the parabola.

To find:

The equation that can be used to model the image of the lens.

Solution:

If the graph of polynomial intersect the x-axis at c, then (x-c) is a factor of the polynomial.

It is given that the image of a lens crosses the x-axis at –2 and 3. It means (x+2) and (x-3) are factors of the function.

So, the equation of the parabola is:

y=k(x+2)(x-3)          ...(i)

Where, k is a constant.

It is given that the point (–1, 2) is also on the parabola. It means the equation of the parabola must be satisfy by the point (-1,2).

Putting x=-1, y=2 in (i), we get

2=k(-1+2)(-1-3)

2=k(1)(-4)

2=-4k

Divide both sides by -4.

\dfrac{2}{-4}=k

-\dfrac{1}{2}=k

Putting k=-\dfrac{1}{2} in (i), we get

y=-\dfrac{1}{2}(x+2)(x-3)

Therefore, the required equation of the parabola is y=-\dfrac{1}{2}(x+2)(x-3).

Note: All options are incorrect.

5 0
3 years ago
Which of the following are remote interior angles of 5
Marizza181 [45]
We need a example please
7 0
3 years ago
What is the equation of the line that passes through the points (-1, 7) and (2, 10) in Standard Form?
Usimov [2.4K]

bearing in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{7})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{10}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{10-7}{2-(-1)}\implies \cfrac{3}{2+1}\implies \cfrac{3}{3}\implies 1

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-7=1[x-(-1)]\implies y-7=x+1 \\\\\\ y=x+8\implies \boxed{-x+y=8}\implies \stackrel{\textit{standard form}}{x-y=-8}

just to point something out, is none of the options, however -x + y = 8, is one, though improper.

3 0
3 years ago
Sasha ran 2/3 of a 27km race before she stopped to walk. How
dimaraw [331]

Answer:

2/3 of 27=18 km

Step-by-step explanation:

3 0
3 years ago
Solve using substitution.<br> y = -x - 1<br> y = x + 3<br> Submit
Alex Ar [27]

Answer:

Step-by-step explanation:

-x - 1 = x + 3

-2x - 1 = 3

-2x = 4

x = -2

y = -2 + 3

y = 1

(-2, 1)

4 0
3 years ago
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