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STatiana [176]
3 years ago
15

Simultaneous equations y=x+2 y=x^2

Mathematics
1 answer:
tigry1 [53]3 years ago
8 0

Answer:

(- 1, 1 ) and (2, 4 )

Step-by-step explanation:

Given the 2 equations

y = x + 2 → (1)

y = x² → (2)

Substitute y = x² into (1)

x² = x + 2 ( subtract x + 2 from both sides )

x² - x - 2 = 0 ← in standard form

(x - 2)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 2 = 0 ⇒ x = 2

x + 1 = 0 ⇒ x = - 1

Substitute these values into (1) for corresponding values of y

x = 2 → y = 2 + 2 = 4 ⇒ (2, 4 )

x = - 1 → y = - 1 + 2 = 1 ⇒ (- 1, 1 )

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Murljashka [212]
5 / 100 = .05
3000(1.05)^2

The answer is $3307.50

Hope this helps :)
4 0
4 years ago
Multiply.
Wewaii [24]
(2/6) × 24 = m
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3 0
3 years ago
Algebraically, find all remaining zeros of f(x) = 8x^3 - 6x^2-36x +27 in simplest form.
viva [34]

Answer:

x=-\frac{3\sqrt{2}}{2},\frac{3}{4},\frac{3\sqrt{2} }{2}

Step-by-step explanation:

Given expression is,

f(x) = 8x³ - 6x² - 36x + 27

For zeros of the function,

f(x) = 0

8x³ - 6x² - 36x + 27 = 0

2x²(4x - 3) - 9(4x - 3) = 0

(2x² - 9)(4x - 3) = 0

(2x² - 9) = 0

x² = \frac{9}{2}

x = \pm\frac{3}{\sqrt{2}}

x = \pm \frac{3\sqrt{2}}{2}

Or (4x - 3) = 0

x = \frac{3}{4}

Therefore, all zeros of the given functions are  x=-\frac{3\sqrt{2}}{2},\frac{3}{4},\frac{3\sqrt{2} }{2}.

7 0
3 years ago
Least to greatest<br> .<br> .<br> .<br> Please and thank you &lt;3
gizmo_the_mogwai [7]
2.2, 5/2, square root of 10, 7/2, -4.8
5 0
2 years ago
If the largest angle of a triangle is 120 degrees and it is included between sides of 1.5 and 0.5, what is the largest side of t
Amanda [17]
C²=a²+b²-2·a·b·cos(C)

c²=(1.5)² + (0.5) -2 ·(l·5) ·(0.5) ·cos(120°)

c²= 3.25

c= √3.25

c=1.802775638

To nearest tenth, c=1.8
3 0
3 years ago
Read 2 more answers
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