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Damm [24]
3 years ago
11

Complete the statements by writing the number

Chemistry
1 answer:
Dovator [93]3 years ago
7 0

Answer:

A) The substance is in the gas phase only in "region 5".

B) The substance is in both the liquid and solid phase in "region 2"

C) The substance is only in the liquid phase in "region 3".

D) The melting point is the temperature at "region 2".

E) The boiling point is the temperature at "region 4".

Explanation:

The graph is a graph of the solid, liquid, vapour phase change diagram.

In phase 1, the substance is ice which is the solid phase.

In phase 2,it undergoes melting in a forward reaction.

In phase 3, the melting from phase 2 has now changed to water which is liquid phase.

In phase 4, the substance is undergoing a forward reaction known as evaporation.

In phase 5, the evaporation from stage 4 will turn the liquid into vapour known as the gas phase.

A) The substance is in the gas phase only in "region 5".

B) The substance is in both the liquid and solid phase in "region 2"

C) The substance is only in the liquid phase in "region 3".

D) The melting point is the temperature at "region 2".

E) The boiling point is the temperature at "region 4".

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The formula for mole fraction is:

mole fraction of solute = \frac{number of moles of solute}{total number of moles of solution}    -(1)

The solubility of oxygen gas = 1.0 mmol/L  (given)

1.0 mmol/L means 1.0 mmol are present in 1 L.

Converting mmol to mol:

1.00 mmol\times \frac{1 mol}{1000 mmol} = 0.001 mol

So, moles of oxygen = 0.001 mol

For moles of water:

1 L of water = 1000 mL of water

Since, the density of water is 1.0 g/mL.

Density = \frac{mass}{volume}

Mass = 1.0 g/ml\times 1000 mL = 1000 g

So, the mass of water is 1000 g.

Molar mass of water = 18 g/mol.

Number of moles of water = \frac{1000 g}{18 g/mol} = 55.55 mol

Substituting the values in formula (1):

mole fraction = \frac{0.001}{55.55+0.001}

mole fraction = 1.8\times 10^{-5}

Hence, the mole fraction is 1.8\times 10^{-5}.

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3 years ago
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What is the volume, in liters, of 5.500 mol of C3H3 gas at STP
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