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lord [1]
3 years ago
7

56.5 g of sodium nitrate is dissolved in water to make 627 g of solution . what is the percent sodium nitrate in the solution

Chemistry
2 answers:
Tamiku [17]3 years ago
8 0

Answer:

9.01%

Explanation:

The following data were obtained from the question:

Mass of sodium nitrate, NaNO3 = 56.5g

Mass of solution = 627g

The percentage composition of sodium nitrate, NaNO3 in the solution can be obtained as follow:

Percentage composition of NaNO3 = Mass of NaNO3/mass of solution x 100

Percentage composition of NaNO3 = 56.5/627 x 100 = 9.01%

Therefore, the percentage composition of sodium nitrate, NaNO3 in the solution is 9.01%

Brrunno [24]3 years ago
8 0

Answer:

The percentage of sodium nitrate in the solution is 9.01%

Explanation:

Here we have;

56.5 g of sodium nitrate dissolved in water to make a solution of mass = 627 kg

Mass of sodium nitrate, NaNO₃, in the solution = 56.5 g

Mass of resultant solution = 627 g

The relation for the percentage of a solute by mass dissolved in a solvent is presented as follows;

Percentage \, by  \, mass = \frac{Mass \, of \, solute}{Mass \, of \, solution} \times 100

Therefor, for the 56.5 g of sodium nitrate solution, we have;

Percentage \, by  \, mass \, of \, NaNO_3 = \frac{Mass \, of \, NaNO_3}{Mass \, of \, solution} \times 100 = \frac{56.5 \, g}{627 \, g} \times 100 = 9.01 \%

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The number of grams of Cl2 formed when 0.385 mol HCl reacts with an excess of O2 is 13.6675 g.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 × 10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

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Now we will compare the moles of Cl₂ with HCl.

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brainly.com/question/8455949

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