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Anastaziya [24]
3 years ago
6

Which of the following is true about the two atoms below?

Chemistry
1 answer:
nordsb [41]3 years ago
4 0

Answer:

Different Number of neutrons.

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Compare the strength of the intermolecular forces in solids liquids and gases
telo118 [61]

Intermolecular forces in solids are strongest than in liquids and gases. Gases have the least strong intermolecular forces. Intermolecular forces are weak and are significant over short distances between molecules (determined by Coulomb’s law). The farther away from the molecules the weaker the intermolecular forces. Since molecules in solids are the closest, the intermolecular force between them as the strongest. Conversely, since gas molecules are farthest apart, the intermolecular forces between them are the weakest.

3 0
4 years ago
How is a shadow created during a lunar or solar eclipse?
Zepler [3.9K]
However, as a result of the Sun's large angular size, solar<span> illumination is only partially blocked in the outer portion of the Earth's </span>shadow<span>, which is given the name penumbra. A penumbral </span>eclipse<span> occurs when the Moon passes through the Earth's penumbra. The penumbra causes a subtle darkening of the Moon's surface.</span>
7 0
3 years ago
I need to find the chemical equation
Yuri [45]

Answer:

2NaCN + CaCO3 --> Na2CO3 + Ca(CN)2

Explanation:

Knowing the names gets us: NaCN + CaCO3 --> Na2CO3 + Ca(CN)2

Balance: there are two sodiums and cyanides on the product side so add a 2 to the reactant side.

4 0
3 years ago
An Argon atom will do which of the following when it forms an ion? Choose all that apply and are correct.
sattari [20]

Answer:

A

Explanation:

Noble gases are already stable

And since Argon is a noble gas it is stable

5 0
3 years ago
Oxycodone (C18H21NO4), a narcotic analgesic, is a weak base with pKb = 5.47. Calculate the pH of a .00500 M oxycodone solution.
Ganezh [65]

Answer:

pH = 10.11

Explanation:

Hello there!

In this case, since it is possible to realize that this base is able to acquire one hydrogen atom from the water:

C_{18}H_{21}NO_4+H_2O\rightleftharpoons C_{18}H_{21}NO_4H^+OH^-

We can therefore set up the corresponding equilibrium expression:

Kb=\frac{[C_{18}H_{21}NO_4H^+][OH^-]}{[C_{18}H_{21}NO_4]}

Which can be written in terms of the reaction extent, x:

Kb=\frac{x^2}{0.00500M-x}=3.39x10^{-6}

Thus, by solving for x we obtain:

x_1=-0.000132M\\\\x_2=0.0001285M

However, since negative solutions are now allowed, we infer the correct x is 0.0001285 M; thus, the pOH can be computed:

pOH=-log(x)=-log(0.0001285)=3.89

And finally the pH:

pH=14-pOH=14-3.89\\\\pH=10.11

Best regards!

5 0
3 years ago
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