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3 years ago

How do I graph -1, -4?

Mathematics

1 answer:

Sonbull [250]3 years ago

4 0

Answer:

Start at the origin and go to the left by one and go down by 4

Step-by-step explanation:

The x coordinate relates to the horizontal axis and the y axis refers to the vertical axis.

Before we start graphing we must always begin at the origin (0,0)

Since the x value is -1 we have to move left by 1 on the x axis

We would move to the left one value because negative is on the left side

For the y value, we would have to move 4 down on the y axis because this number is also negative.

So your graph should look like this

Hope this helps :)

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F(x)=70n-400 how many students must be enrolled in the class for the instructor to make a profit?

BigorU [14]

Answer:

6 students must be enrolled.

Step-by-step explanation:

F(x) must be greater than 0. Thus, 70*n-400 must be greater than 0.

70*n -400 >0

70*n > 400

n > 400/7

n > 5.7

n >6

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3 years ago

How can you tell the difference between a rectacle and rhombus

Morgarella [4.7K]

A square is a type of rectangle, just one where all four sides are the same length. Finally, there's the rhombus, which is a four-sided shape with sides of equal length. The angles can be 90 degrees, but they don't need to be. So, a square is a rhombus, but not every rhombus is a square.

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4 years ago

Read 2 more answers

Apply Newton’s method to estimate the solution of x3 − x − 1 = 0 by taking x1 = 1 and finding the least n such that xn and xn +

ss7ja [257]

Solution :

Given

$f(x)=x^3-x-1, x_1=1$

$f'(x)=3x^2-1$

Let the initial approximation is $x_1 =1$

So by Newton's method, we get

$x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)},n=1,2,...$

$x_2=x_1-\frac{f(x_1)}{f'(x_1)}=1-\frac{1^3-1-1}{3(1)^2-1}=1.5$

$x_3=1.5-\frac{(1.5)^3-1.5-1}{3(1.5)^2-1}=1.34782608$

$x_4=1.34782608-\frac{(1.34782608)^3-1.34782608-1}{3(1.34782608)^2-1}=1.32520039$

$x_5=1.32520039-\frac{(1.32520039)^3-1.32520039-1}{3(1.32520039)^2-1}=1.32471817$

$x_6=1.32471817-\frac{(1.32471817)^3-1.32471817-1}{3(1.32471817)^2-1}=1.32471795$

$x_5 \approx x_6$ are identical up to eight decimal places.

The approximate real root is x ≈ 1.32471795

∴ x = 1.32471795

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3 years ago

Help please. I need assistance

madam [21]

The first translation is 3 units to the right giving in new equation
y = sqrt(x - 3)

then translation of 2 units vertically upwards makes
h(x) = sqrt(x - 3) + 2

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3 years ago

16 2/3% of 21.6 is?

soldier1979 [14.2K]

Answer:

Step-by-step explanation:

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