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Daniel [21]
3 years ago
6

The image of (6, 9) under a dilation is (4, 6).

Mathematics
2 answers:
Ad libitum [116K]3 years ago
8 0
For this case we have the following ordered pairs:
 (6, 9)
 (4, 6)
 The scale factor can be found in two different ways:
 k = 6/4 = 3/2 = 1.5

k = 9/6 = 3/2 = 1.5
 Therefore, the scale factor is given by:
 k = 1.5

 Answer:
 
The scale factor of the dilation is 1.5
choli [55]3 years ago
4 0

Answer:

2/3.

Step-by-step explanation:

The exercise says us that we multiply (6,9) by a factor (in the enunciated is called a dilation) and obtain (4,6). That is

(6,9)x=(6x,9x) = (4,6). (in the exercise the x is represented with a0)

Now, one ordered pair is equal to another if both first components are equal and also if both second components are equal. Then,

6x = 4 and 9x=6

x = 4/6 and x = 6/9

x = 2/3 and x= 2/3.

So, the scale factor of the dilation is 2/3.

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The temperature, H, in degrees Celsius, of a cup of coffee placed on the kitchen counter is given by H = f(t), where t is in min
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Answer:

a

    f'(t) is  negative

b

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c

At <u>35</u> minutes after the coffee was put on the counter, its temperature is <u>68</u> and will <u>decrease</u> by about <u>0.75</u> in the next 30 seconds.          

Step-by-step explanation:

From the question we are told we are told that  

   The  equation for the temperature of a cup of coffee place on a counter is

         H= f(t)

Here  t is the time in minutes the  coffee was put on the counter

Generally  f(t)'  is the derivative of  f(t) at it represents the change of the temperature of the cup of coffee with respect to time

 Generally for the coffee placed on the counter after a couple of minutes the temperature will decrease hence  f(t)' is  negative

Generally the unit of the temperature is in degrees Celsius while that of time is  in minutes

  So the change in temperature with time f(35)' will be in degrees Celsius/minutes (i.e  degC/min)

  From the question we are told that

        |f(35)'| =  1.5

i.e  the rate of change of temperature after 35 minutes is  1.5

and

         |f(35)| =  68

i.e the temperature of the cup of coffee after 35 minutes is  67 degC

Now after another   t=  30  seconds =  \frac{30}{60}= 0.5 \ minutes the  rate  of change of the temperature of the cup of  coffee is  

          R =  |f(35)'| *  t

=>        R = 1.5  *  0.5

=>        R = 0.75    

So

At <u>35</u> minutes after the coffee was put on the counter, its temperature is <u>68</u> and will <u>decrease</u> by about <u>0.75</u> in the next 30 seconds.  

     

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