-n/3=4
-n/3 x 3=4 x 3
-n=12
-n/-1=12/-1
n=-12
(4,-16) factor 3/4
3/4 ×4=3 , -16×3/4= -12
B' (3,-12)
0.405, 0.45 , 0.5 , 4.5 : Least to greatest!
Answer: -2 4/15
Step-by-step explanation: To properly subtract, we need to find a common denominator. We can list the multiples of 3 and 5 to find the common denominator:
3: 3, 6, 9, 12, 15
5: 5, 10, 15
The first common multiple we see is 15.
Calculation:
3 · 3 = 9
9 + 1 = 10
3 1/3 = 10/3
5 x 5 = 25
25 + 3 = 28
-5 3/5 = -28/5
Now to convert into fifteen as the denominator:
-28/5 = -28 x 3/5 x 3 = -84/15
10/3 = 10 x 5/3 x 5 = 50/15
Now to subtract accordingly:
50/15 - 84/15 = -34/15
Final answer: -34/15 (can be reduced to -2 4/15).
The given equation is the best line that approximates the linear
relationship between the midterm score and the score in the final exam.
- AJ's residual is 0.3, which is not among the given options, therefore, the correct option is. <u>E. None of these</u>.
Reasons:
The given linear regression line equation is;
= 25.5 + 0.82·
Where;
= Final exam score;
= The midterm score;
AJ score in the first test,
= 90
AJ's actual score in the exam = 99
Required:
The value of AJ's residual
Solution:
By using the regression line equation, we have;
The predicted exam score,
= 25.5 + 0.82 × 90 = 99.3
- The residual score = Predicted score - Actual score
∴ AJ's residual = 99.3 - 99 = 0.3
AJ's residual = 0.3
Therefore, the correct option is option E;
Learn more about regression line equation here:
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