Given:
In triangle XYZ, x = 27 cm, y = 79 cm and
.
To find:
The length of z.
Solution:
In triangle XYZ, using the Law of cosine, we get
![z^2=x^2+y^2-2xy\cos Z](https://tex.z-dn.net/?f=z%5E2%3Dx%5E2%2By%5E2-2xy%5Ccos%20Z)
Putting the given values in the above formula, we get
![z^2=(27)^2+(79)^2-2(27)(79)\cos (142^\circ)](https://tex.z-dn.net/?f=z%5E2%3D%2827%29%5E2%2B%2879%29%5E2-2%2827%29%2879%29%5Ccos%20%28142%5E%5Ccirc%29)
![z^2=729+6241-4266(-0.788)](https://tex.z-dn.net/?f=z%5E2%3D729%2B6241-4266%28-0.788%29)
![z^2=6970+3361.608](https://tex.z-dn.net/?f=z%5E2%3D6970%2B3361.608)
![z^2=10331.608](https://tex.z-dn.net/?f=z%5E2%3D10331.608)
Taking square root on both sides.
![z=\pm \sqrt{10331.608}](https://tex.z-dn.net/?f=z%3D%5Cpm%20%5Csqrt%7B10331.608%7D)
![z=\pm 101.6445178](https://tex.z-dn.net/?f=z%3D%5Cpm%20101.6445178)
Approx the above value to the nearest number and side length cannot be negative. So,
![z\approx \pm 102\text{ cm}](https://tex.z-dn.net/?f=z%5Capprox%20%5Cpm%20102%5Ctext%7B%20cm%7D)
Therefore, the length of z is about 102 cm.
Each room would be 1 hour because it say that two rooms get painted in two hours <span />
Answer:
![\frac{ - 13}{15}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20-%2013%7D%7B15%7D%20)
Step-by-step explanation:
![\frac{ - 11}{15} + \frac{ - 2}{15} = \frac{( - 11 - 2)}{15} = \frac{ - 13}{15}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20-%2011%7D%7B15%7D%20%20%2B%20%20%5Cfrac%7B%20-%202%7D%7B15%7D%20%20%3D%20%20%5Cfrac%7B%28%20-%2011%20-%202%29%7D%7B15%7D%20%20%3D%20%20%20%5Cfrac%7B%20-%2013%7D%7B15%7D%20)
You would mutiple 22000 by 5 then divide that by .2 and that would be your answer
Answer:
-100x^2+1730x+350 - Standard from