So here is how we are going to prove that (2(tan x - cot x) / (tan^2 x - cot^2 x} = sin (2x). Follow it step by step:
LS = 2(tanx−cotx)
------------------
tan^2−cot^2x
= 2(tanx−cotx)
----------------------
(tanx−cotx)(tanx+cotx)
= 2
-------------------
(tanx+cotx)
= 2
-----------------
Sin2x+cos2x
---------------- sinxcosx
= 2
-------------
1
------------
sinxcosx
= 2sinxcosx
= sin2x
I hope that is the answer that you are looking for. Let me know if you need more help next time. Thanks for posting your question here in brainly!
The answer is A because of base times height
Answer:
(A)Cost of Rental A, C= 15h
Cost of Rental B, C=5h+50
Cost of Rental C, C=9h+20
(B)
i. Rental C
ii. Rental A
iii. Rental B
Step-by-step explanation:
Let h be the number of hours for which the barbeque will be rented.
Rental A: $15/h
Rental B: $5/h + 50
- Cost of Rental B, C=5h+50
Rental C: $9/h + 20
- Cost of Rental C, C=9h+20
The graph of the three models is attached below
(b)11.05-4.30
When you keep the barbecue from 11.05 to 4.30 when the football match ends.
Number of Hours = 4.30 -11.05 =4 hours 25 Minutes = 4.42 Hours
-
Cost of Rental A, C= 15h=15(4.42)=$66.30
- Cost of Rental B, C=5h+50 =5(4.42)+50=$72.10
- Cost of Rental C, C=9h+20=9(4.42)+20=$59.78
Rental C should be chosen as it offers the lowest cost.
(c)11.05-12.30
Number of Hours = 12.30 -11.05 =1 hour 25 Minutes = 1.42 Hours
- Cost of Rental A, C= 15h=15(1.42)=$21.30
- Cost of Rental B, C=5h+50 =5(4.42)+50=$57.10
- Cost of Rental C, C=9h+20=9(4.42)+20=$32.78
Rental A should be chosen as it offers the lowest cost.
(d)If the barbecue is returned the next day, say after 24 hours
- Cost of Rental A, C= 15h=15(24)=$360
- Cost of Rental B, C=5h+50 =5(24)+50=$170
- Cost of Rental C, C=9h+20=9(24)+20=$236
Rental B should be chosen as it offers the lowest cost.
Answer:
= 2
Step-by-step explanation:
Step 1- Substitute the variables
(2(4)-2)÷3
Step 2- Multiply
(2(4)-2)÷3
Step 3- Subtract
(8-2)÷3
Step 4- Divide
6÷3=2
Answer:X=14,/ integers are-14,16,18,20
Step-by-step explanation: