Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
First distribute in the 2 on the left side to get 6d+6=7+6d
Then, you would combine the variables to be on one side of the equation by doing -6d. However, this would cancel out the d by leaving you with 0d+6=7. That is the same thing as saying 6=7.
The answer to this equation is no solution because 6 is NOT equal to 7.
Answer:
You are correct
Step-by-step explanation:
Start with 1 1/2. This can be made into an improper fraction which is 3/2
Now multiply both top and bottom of 3/2 by 5
(3*5)/(2 * 5) = 15 / 10
16/10 is just slightly bigger than 15/10
Answer:
28/5 or 5 3/5
Step-by-step explanation:
First you need to make the mixed number into an improper fraction, like this:
3 1/2 turns into 7/2
Next you will need to do the reciprocal of division and inverse operation:
7/2 times 8/5
Then solve it:
7/2 * 8/5 = 56/10
Last simplify:
28/5
or
5 3/5
Answer:
0.8
Step-by-step explanation:
