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2 years ago

A square has an area of 196 square centimeters. What is the length of each side?

Mathematics

1 answer:

kozerog [31]2 years ago

7 0

Answer:

The answer is simply 49.

Step-by-step explanation:

196 ÷ 4 is why because their are 4 sides on a square if you divide it by 4 you get the answer 49. You're probably in like 3rd grade or smth this is so easy.

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Carl has 200 songs on MP3 24 songs are country what is the percentage of his country songs

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12%. since this 24/ 200 if you just divide it by 2 you get 12/ 100 meaning 12%

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3 years ago

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“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor

Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

$C=2\pi r$

Find the radius of the sphere with a 5.50-meter circumference

For $C=5.50\ m$

assume

$\pi =3.14$

substitute and solve for r

$5.50=2(3.14)r$

$r=5.50/[2(3.14)]=0.88\ m$

Find the radius of the sphere with a 7.85-meter circumference

For $C=7.85\ m$

assume

$\pi =3.14$

substitute and solve for r

$7.85=2(3.14)r$

$r=7.85/[2(3.14)]=1.25\ m$

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

$SA=4\pi r^{2}$

Find the surface area of sphere with a 5.50-meter circumference

For $r=0.88\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(0.88)^{2}$

$SA=9.73\ m^{2}$

Find the surface area of sphere with a 7.85-meter circumference

For $r=1.25\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(1.25)^{2}$

$SA=19.63\ m^{2}$

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

Find the cost of sphere with a 5.50-meter circumference

$9.73*(92)=\$895.16$

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Find the cost of sphere with a 7.85-meter circumference

$19.63*(92)=\$1,805.96$

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

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3 years ago

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John brought 20 water melons each water melon cost him 2 dollars. He gave his friend Bob 3/4 of the watermelons. In return bob gave him double the amount of water melons back. How many watermelons does John have now? How much money did he spend on each water melon?

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3 years ago

How does a compass and straightedge help you make a triangle

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Answer:

A compass and straightedge allow for a more accurate rendition of a triangle, especially one needed to be specific measures

Step-by-step explanation:

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3 years ago

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Answer:

4/5

Step-by-step explanation:

To get the answer, find the GCF (greatest common factor) of the numerator and the denominator. Once you have the GCF, divide the 12 and 15 by that number. Here, the GCF is 3.

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