Answer is 120
AngNPQ=2*angNRQ=120
Answer:
4
hours
i hope that helped
Step-by-step explanation:
You can drag in the first empty box ∡3 and get ∡2≅∡3.
In the second box you can drag '' definition of angle bisector ''.
In the third empy box you can drag ∡1 and get ∡1≅∡3.
At last empy box you can drag ''transitive property of congruence''
Good luck!!!
Answer: Choice B
y = (x+3)^2 - 1
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Recall that vertex form is y = a(x-h)^2 + k with the vertex being (h,k)
From the given graph, it shows that (h,k) = (-3,1) is the vertex. So we plug this pair of values into the general function above to get
y = a(x-h)^2 + k
y = 1(x-(-3))^2 + (-1)
y = (x+3)^2 - 1
which is the final answer
note: a = 1 is the case for all four answer choices, so we don't have to worry about the value of 'a'