By pythagorean thoerm u can find
Hy^2=length^2+base^2
The total area of the room is 37.6376 and the no. of cans required to paint the wall is 3 cans.
The measurement of two of the walls is 2.86 metres and 3.16 metre
Area of the two walls = 2(length x breadth)
Area = 2(2.86 x 3.16) = 18.0752 m²
The measurement of the other two walls is 2.86 metres and 3.42 metres
Area of the two walls = 2(length × breadth)
Area = 2(2.86 × 3.42) = 19.5624 m²
Total area = 18.0752 + 19.5624 = 37.6376 m²
If one can of paint can cover 15 m², the no. of cans required to paint the bedroom will be
No. of cans = Total area/Area covered by one can of paint
No. of cans = 37.6376/15 = 2.5091 = 3 cans (approx.)
Answer:
(-1, 0)
Step-by-step explanation:
5 is the x value which is left and right, so you said u move left 6 units. Since the 5 is positive and left is negative; 5-6= -1. 3 is the y value which is up and down (vertical), so you said u move down 3 units, since the 3 is positive, when you move down that is negative; so 3-3=0.
Question:
Solution:
Note that :

where the left hand of the equation represents a trinomial and the right hand of the equation represents a product of two binomials. Then, we can conclude that the correct answer is:
B