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irina1246 [14]
2 years ago
6

... Stella uses the expression 0.40a, where a is the original attendance at a play, to find the reduced attendance at the next p

erformance. Which is an equivalent expression?
Mathematics
1 answer:
Dmitry_Shevchenko [17]2 years ago
8 0

The expression that is equivalent to 0.40a is \frac 25a

<h3>What are equivalent expressions?</h3>

Equivalent expressions are expressions that have equal values, when evaluated or simplified

The expression is given as:

0.40a

Rewrite the above expression as a fraction

\frac 4{10}a

Simplify the fraction

\frac 25a

Hence, an equivalent expression of 0.4a is \frac 25a

Read more about equivalent expressions at:

brainly.com/question/2972832

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maksim [4K]

-4(3-x)+6=2(x-3) -12+4x+6=2x-6 -6+4x=2x-6 -6+6=2x-4x 0=-2x 0/x=-2

4 0
3 years ago
please help! functions and relations. f(x)= square root of x-4. find the inverse of f(x) and it’s domain.
likoan [24]

ANSWER:

\:D.\text{ }f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge-4

STEP-BY-STEP EXPLANATION:

We have the following equation:

f(x)=\sqrt{x}-4

The inverse is the following (we calculate it by replacing f(x) by x and x by f(x)):

\begin{gathered} x=\sqrt{f^{-1}(x)}-4 \\  \\ \sqrt{f^{-1}(x)}=x+4 \\  \\ f^{-1}(x)=(x+4)^2 \end{gathered}

The domain would be the range of the original equation, and it would be the range of values that f(x) could take, which was from -4 to positive infinity, that is, f(x) ≥ -4.

Therefore, the domain is x ≥ -4.

So the correct answer is D.

\:f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge -4

4 0
1 year ago
How many real-number solutions does the equation have?
Nataly_w [17]

Answer:

Option b. Two solutions

Step-by-step explanation:

In order to find how many real number solutions the equation has we have to solve it

Given equation: -4x² + 10x + 6 = 0

taking 2 common from the equation

2(-2x² + 5x + 3) = 0

-2x² + 5x + 3 = 0

taking minus sign common from the above equation

2x² - 5x - 3 = 0

We will solve this equation by factorization in such a way that the sum of two factors is equal to -5x and the product is -6x²

2x² - 6x + x - 3 = 0

taking common above

2x(x-3) + 1(x-3) = 0

taking (x-3) common

(2x+1)(x-3) = 0

2x + 1 = 0

2x = -1

x = \frac{-1}{2}

x - 3 = 0; x = 3

the solutions are

x=\frac{-1}{2},3

Both values are real numbers, therefore correct option is b

7 0
3 years ago
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The answer to this problem is -90.05.


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