The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
(a) You can plant 7 1/4 acres per pound of seed
(b) Isabel takes 7 minutes to run a mile
First compute the coefficient like this:
Simplifying the fraction over 4! we get:
and the variables are
. So answer
.
The correct answer is C then.
Answer:
64 * b * b * b * b * b * b
Step-by-step explanation:
Apply exponent to number first, then expand the variable's exponent into repeated multiplication.
Answer:
Yes
Step-by-step explanation:
21/3=7
15/3=5
