Answer:
The answer to your question is: third option is correct
Step-by-step explanation:
According to the graph we can see that the points where both lines crosses are:
A (4, 8) and B (-4, 0)
Answer:
v = 8.49 m/s rounded off to 3 significant figures
Step-by-step explanation
Using Energy Conservation
U = Tk + Vp (Sum of kinetic Tk Energy and gravitational potential Vp Energy)
- At height = 3.67 m, the hammer was still or the velocity was negligible; hence, vi = 0 m/s.
- Ui = 0 + mgh
- At ground all potential energy is converted to kinetic; hence, Uf =
mv². - Since total energy of the system remains constant we equate Ui to Uf.
- Ui = Uf
- mgh = mv²
- After cancelling out masses and making v the subject of the formula we get:
v = ![\sqrt[2]{2gh}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B2gh%7D)
= ![\sqrt[2]{2*9.81*3.67}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B2%2A9.81%2A3.67%7D)
= 8.49 m/s rounded off to 3 significant figures
Answer:
99 yd
Step-by-step explanation:
When I add these, I line them up vertically
29 yd. 2ft. 11 in.
+ 55 yd. 1 ft. 10 in.
+ 13 yd. 1 ft. 3 in.
---------------------------
97 yd 4ft 24 in
We know that 12 in = 1 ft
so 24 in = 2ft
Subtract 24 in and add 2 ft
97 yd 4ft 24 in
+2ft -24 in
------------------------------
97 yd 6ft
We know 3 ft = 1yd
so 6ft = 2yd
Subtract 6ft and add 2 yd
97 yd 6ft
+2yd - 6ft
-------------------
99 yd
2 meters equals to 200 centimeters and then you do 200 divided by 10 which 20 and 20 is the answer!
