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N76 [4]
3 years ago
10

I’m confused please help

Mathematics
1 answer:
kupik [55]3 years ago
5 0
Ne demek istiyosun anlamadım
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Please please please helppp!!! BRAINLIEST FOR CORRECT ANSWER! Erin made a mistake when writing a transformation rule to translat
alukav5142 [94]

Answer:

a. The x and the y values are flipped, it reads left 2 down 4

b. it should be (x+4, y+2)

Step-by-step explanation:

when it is plus on x it is left and when it is negative on y it is down

6 0
3 years ago
19. Find the least common multiple of x² + 4x +3 and x² + 7x + 12.
Tems11 [23]

Answer:

  C.  (x +1)(x +3)(x +4)

Step-by-step explanation:

The least common multiple is the product of the unique factors of each of the expressions. To find it, we need to factor each expression and identify the unique factors.

__

<h3>factorization</h3>

  x² +4x +3 = (x +3)(x +1)

  x² +7x +12 = (x +3)(x +4)

<h3>LCM</h3>

The unique factors are (x +1), (x +3), (x +4). The LCM is their product:

  LCM = (x +1)(x +3)(x +4)

_____

<em>Additional comment</em>

The positive sign of the constant (+3, +12) in each case tells you that the constants in the binomial factors will have the same sign. The positive sign of the linear term (+4x, +7x) in each case tells you the binomial factors will have constants with a positive sign. So, all of the answer choices that have negative constants can be eliminated.

3 0
2 years ago
Evaluate the expression when y = 2.
fomenos
Well.... collect like terms
y+(4+7) than you simplify it y+11 so what is 11+7??
its 18!!!
3 0
3 years ago
What is 3x9x-5x=7#hh&amp;
Paha777 [63]

move the 3 to the 7 side. it will become negative.

9x-5x=7-3

4x=4

x=1

7 0
3 years ago
Suppose that the sitting​ back-to-knee length for a group of adults has a normal distribution with a mean of mu equals 22.1 in.
nadya68 [22]

Answer:

Step-by-step explanation:

Given that  the sitting​ back-to-knee length for a group of adults has a normal distribution with a mean of mu equals 22.1 in. and a standard deviation of sigma equals 1.2 in.

We have to find values of x such that

P(X\geq a) \leq 0.01\\ and

P(X\leq b) \leq 0.01

a=2.33 and b =-2.33 as z values

Let us convert to X values

x=22.1-2.33(1.2) \\x=22.1+2.33(1.2)\\

i.e. values below 19.304 and above 25.496

Hence for x below 19.304 and above 25.496 are significantly low and high.

24.2 length is not significantly high.

4 0
3 years ago
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