The answer could be a fracture. Hope this helps!!
Answer:
B
Explanation:
I did this and got it right
Explanation:
After repeated stimulation by antigen, B cells can make antibodies that bind their antigen with much higher affinity a process called affinity maturation. ... Thus, antigen stimulation greatly increases the antibody arsenal. Antibodies are proteins, and proteins are encoded by genes.
It greatly increases the surface area which makes more space for all of the complexes of the electronic transport system.
Answer:
7%.
Explanation:
The recombinant progeny might occur due to the exchange of genetic material between non sister chromatids known as crossing over during the meiosis.
The chromosome sequence is DABC. A and B distance is 4 map units, B and C is 2 map units, B and D is 5 map units. The distance between A and D is 1 map unit that can be calculated by subtracting the distance between BD and AB ( 5-4). The CD map distance can be calculated by adding the distance between AD, AB and BC ( 1 + 4+ 2). The recombination frequency is equal to distance between them is 7%.
Thus, the answer is 7%.
