Is this a graphing question or…
Answer:


Step-by-step explanation:
We are given that c=6 units


We have to find the side length a and b.
We know that sum of angles of a triangle =180 degrees

Substitute the values then we get



sine law: 






Answer:
Step-by-step explanation:
5c + 4f ≥ 200
c + f ≤ 60
c > 0
f > 0
4. Supplementary angles together make a straight line (two right angles). So BOE is supplementary to BOC
Answer: ∠BOE
5. Distance and midpoint between (4,-2), (6,8)

midpoint

Answer: distance 2√26, midpoint (5, 3)
6.That's a rectangle oriented parallel to the axes, width parallel to the x axis of 7 - -3 = 10 and length along y of 1 - - 4 = 5, so an area of 10(5)=50
Answer: 50