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Neporo4naja [7]
3 years ago
7

Which graph shows h(x) = f(x)/g(x)

Mathematics
1 answer:
pogonyaev3 years ago
7 0

Answer:

What is the graph of h(x)=f(x)+g(x) with an example?

So many possible combinations of types of equations for f(x) and g(x).

If they are both linear. f(x) = 3x + 2. g(x) = 2x - 5. h(x) = f(x) + g(x) = 5x - 3. This is also linear.

f(x) has slope = 3 and y-intercept = 2. g(x) has slope = 2 and y intercept = -5. h(x) has slope = 5 and y-intercept = -3.

The graph of the sum of two linear equations is a straight line with slope equal to the sum of the slopes of the two linear equations and a y-intercept equal to the sum of the y-intercepts of the two linear equations.

If one is linear and the other is quadratic. f(x) = 2x + 3. g(x) = x^2 + 6x - 4. h(x) = f(x) + g(x) = x^2 + 8x - 1. This is quadratic.

f(x) has slope = 3 and y-intercept = 3. g(x) has an axis of symmetry of x = -3, vertex at (-3, -13), y-intercept = -4, x-intercepts = -3 + 13^½ and -3 - 13^½ . h(x) has an axis of symmetry of x = -4, vertex at (-4, -17), y-intercept = -1, x-intercepts = -4 + 17^½ and -4 - 17^½ .

The graph of the sum of a linear equation [y = mx + b] and a quadratic equation [y = Ax^2 + Bx + C] has an axis of symmetry of x = - (B + m) / 2A, vertex at ( - (B + m) / 2A, - (B + m)^2 / 4A + (b + C)), y-intercept = b + C, x-intercepts = (- (B + m) + ( (B + m)^2 - 4A (b + C))^½ ) / 2A and (- (B + m) - ( (B + m)^2 - 4A (b + C))^½ ) / 2A .

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A software engineer is creating a new computer software program. She wants to make sure that the crash rate is extremely low so
Soloha48 [4]

Answer:

a) the sample size is 400

b) 95% confidence Interval for p is ( 0.0286, 0.0714 )

Step-by-step explanation:

Given the data in the question;

sample size n = 400

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p = x / n = 20 / 400 = 0.05

q = 1 - p = 1 - 0.05 = 0.95

a)

n = 400

Hence, the sample size is 400

b) 95% confidence Interval for p;

At 95% confidence interval,

significance level ∝ = 1 - 95% = 1 - 0.95 = 0.05

∝/2 = 0.05 / 2 = 0.025

so, Z critical Value ; Z_{\alpha /2 = 1.96  { from table }

So for Confidence Interval for p;

⇒ p' ± Z_{\alpha /2√( p'q' / n )

we substitute

⇒ 0.05 ± 1.96√( (0.05 × 0.95 ) / 400 )

⇒ 0.05 ± 1.96√( 0.00011875 )

⇒ 0.05 ± 1.96 × 0.010897

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⇒ ( 0.05 - 0.021358 ), ( 0.05 + 0.021358 )

⇒ ( 0.0286, 0.0714 )

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Step-by-step explanation:

From the question, we are informed that Chef bought 3 3/4 kilograms of apples 7 1/4 kilograms of pears and 10 1/8 kilograms of oranges. The total kilogram of fruits bought would be:

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Note that the Lowest Common Multiple is 8.

= 3 6/8 + 7 2/8 + 10 1/8

= 20 9/8

= 21 1/8 kilogram

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