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AlladinOne [14]
4 years ago
8

A television programmer is arranging the order that seven movies will be seen between the hours of 6 P.M. and 8 A.M. Two of the

movies have a G​ rating, and they are to be shown in the first two time blocks . One of the movies is rated​ NC-17, and it is to be shown in the last of the time​ blocks, from 6 A.M. until 8 A.M. Given these​ restrictions, in how many ways can the seven movies be arranged during the indicated time​ blocks?
Mathematics
1 answer:
Sonja [21]4 years ago
3 0

A television programmer is arranging the order that seven movies will be seen between the hours of 6 P.M. and 8 A.M. Two of the movies have a G​ rating, and they are to be shown in the first two time blocks . One of the movies is rated​ NC-17, and it is to be shown in the last of the time​ blocks, from 6 A.M. until 8 A.M. Given these​ restrictions the movie can be arrange in:

2*1*4*3*2*1*1 ways = 48 ways

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Can somebody answer this? thankyu​
kvasek [131]

Answer:

1. 3, 12, 48, 192, 768               Ratio: x4

2. 8, 16, 32, 64, 128                Ratio: x2

3. 120, 60, 30, 15, 7.5             Ratio: ÷2

4. 5, 10, 20, 40, 80, 160          Ratio: x2

5.  1.3?, 4, 12, 36, 108, 324      Ratio: x3

Hope this helps!

I'm not sure about the first one on question 5 though.

8 0
3 years ago
Find the image of the given point
Ira Lisetskai [31]

Answer:

P' = (2, -6)

Step-by-step explanation:

In this translation, you just need to substitute x and y into the given translation to find what P' is. (x is -6 since it's the x-value of P, and y is -2 since it's the y-value of P):

where T(x, y) = (x + 8, y - 4) and x = -6 and y = -2,

T(-6, -2) = ((-6) + 8), (-2) - 4) (substitute x and y into the translation)

T(-6, -2) = (2, -6) (add and subtract)

So, P' = (2, -6)

6 0
3 years ago
A Niffler is a magical creature who loves to collect shiny objects and store them in their pouch, much like a kangaroo. The amou
Fudgin [204]

Answer:

Probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.

Step-by-step explanation:

We are given that the amount a Niffler can hold in their pouch is approximately normally distributed with a mean of 25 pounds of shiny objects and a standard deviation of 6.8 pounds.

Let X = <u><em>amount a Niffler can hold in their pouch</em></u>

So, X ~ Normal(\mu=25,\sigma^{2} =6.8^{2})

The z score probability distribution for normal distribution is given by;

                                Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 25 pounds

            \sigma = standard deviation = 6.8 pounds

Now, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is given by = P(X > 32 pounds)

  P(X > 32 pounds) = P( \frac{X-\mu}{\sigma} > \frac{32-25}{6.8} ) = P(Z > 1.03) = 1 - P(Z \leq 1.03)

                                                             = 1 - 0.8485 = 0.1515

<em>The above probability is calculated by looking at the value of x = 1.03 in the z table which has an area of 0.8485.</em>

<em />

Hence, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.

4 0
3 years ago
Please help soon.
Anton [14]

Answer:

D. 12

Step-by-step explanation:

D is the closest answer. -2 multiplied by a -1.8 is a +3.6. Then, you add 8 to 3.6 and you will get 11.6. Therefore, the answer you will put is D or 12

7 0
3 years ago
Find the length of DA
olga nikolaevna [1]
If both lines are same length then 7+3=10
5 0
3 years ago
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