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mestny [16]
3 years ago
6

Find the length of DA

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
5 0
If both lines are same length then 7+3=10
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Average Inventory The Yasuko Okada Fragrance Company (YOFC) receives a shipment of 400 cases of specialty perfume early Monday m
Ksenya-84 [330]

Answer:

Step-by-step explanation:

At the end of any given business day, CFFC has 400-80t cases of perfume on hand, where t = 1 represents Monday, t = 2 represents Tuesday and so on. The inventory becomes nil on Friday evening. So,

The values of a and b are

a = 0

b = 5

Using the formular for average value, we have the average value as

\frac{1}{5-0}\int\limits^5_0 {(400-80t)}dt\\\\=\frac{1}{5}(400t-\frac{80t^2}{2})\limits^5_0\\\\=\frac{1}{5}(400t-40t^2)\limits^5_0\\\\=\frac{1}{5}(2000-1000)\\\\=200

Average inventory is 200 cases

8 0
3 years ago
Help me please 25 points.
sveticcg [70]

The answer i got is VP<------------->

AKA the first option

i hope this is right  

4 0
3 years ago
Read 2 more answers
WILL GAVE BRAINLIST!! Use the zero product proper to find the solutions to the equation x^2-x-6=0
Kruka [31]
(x-3)(x+2)=0

x= 3 and x= -2
5 0
3 years ago
Help me lol !! will give brainleist
katovenus [111]

Answer:

28

Step-by-step explanation:

Since, Sum of triangle is equal to 180°

180 = 2x + 50 + 3x - 10

180 = 5x + 40

180 - 40 = 5x

140 = 5x

140/5 = x

28 = x

3 0
2 years ago
Read 2 more answers
HELP PLEASE!!!
ch4aika [34]

Answer:

The population of Bear in 2050 is 4750000

Step-by-step explanation:

A) The exponential growth equation for bear is as follows -

dN/dT = rmax * N

Where dN/dT = change in population

rmax is the maximum rate of change

N = Base population

B) Here the per capita rate of increase (r) will always be a positive value irrespective of the and hence we will assume this population to be growing exponentially.

C) dN/dT = rmax * N

D) dN / 5 = 2.5 * 380,000

dN = 5*2.5 * 380000

= 4750000

8 0
3 years ago
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