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barxatty [35]
3 years ago
9

Find the value of x please

Mathematics
1 answer:
vlada-n [284]3 years ago
5 0

Answer:

hope that help u

Step-by-step explanation:

To find the value of x, bring the variable to the left side and bring all the remaining values to the right side. Simplify the values to find the result. Standard Equation. The standard form to find the value of X in multiplication operation is. Divisor × Dividend = Product. Let us take dividend = x, Divisor × x = Product

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Write and equation given slope and a point. <br> M= -1 and (-2,3)
ArbitrLikvidat [17]

Step-by-step explanation:

y - 3 = -1(x- -2)

y-3 = -x -2

Y = -x +1

3 0
3 years ago
En la preparación de un perfume se cuenta con dos tipos de esencia base: 1600 ml de una y 1680 ml de otra. Se quiere envasarlas,
Lostsunrise [7]

Answer:

33,600 frascos

Step-by-step explanation:

Resolvemos esta pregunta utilizando el método mínimo común múltiple

Encuentre y enumere los múltiplos de 1600 y 1680 hasta encontrar el primer múltiplo común. Este es el mínimo común múltiplo.

Múltiplos de 1600:

1600, 3200, 4800, 6400, 8000, 9600, 11200, 12800, 14400, 16000, 17600, 19200, 20800, 22400, 24000, 25600, 27200, 28800, 30400, 32000, 33600, 35200, 36800

Múltiplos de 1680:

1680, 3360, 5040, 6720, 8400, 10080, 11760, 13440, 15120, 16800, 18480, 20160, 21840, 23520, 25200, 26880, 28560, 30240, 31920, 33600, 35280, 36960

Por lo tanto,

LCM (1600, 1680) = 33,600

La menor cantidad de frascos necesarios es 33,600 frascos.

4 0
3 years ago
Solve for m.t=mr^2/3
spin [16.1K]

t = mr^2/3

Divide both sides by r^2/3

m = t / r^2/3

6 0
3 years ago
Read 2 more answers
I need help on this question. ​
Montano1993 [528]

Answer:

JK = 30 .

Step-by-step explanation:

As JMLK is a kite the diagonals bisect each other at right angles so triangle JNK is a right triangle.

JK^2 = 18^2 + 24^2 = 900

JK = 30.

8 0
2 years ago
A car travels 150 miles in 2 hours. Which of the following represents a corresponding unit rate? Choose all that apply.
azamat
The answer is C.) 1.25 miles per day
6 0
3 years ago
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