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exis [7]
3 years ago
11

A mating of two people of medium height (where three genes control height): AaBbCc x AaBbCc produce _____ distinct phenotypes de

termined by the number of genes inherited.A. oneB. twoC. fiveD. sevenE. ten
Biology
1 answer:
Ede4ka [16]3 years ago
3 0

<u>Answer:</u>

A mating of two people of medium height (where three genes control height): AaBbCc x AaBbCc produce <u>Seven</u> distinct phenotypes determined by the number of genes inherited.

Option: (D)

<u>Explanation:</u>

  • Traits are the characters that we observe. When the parents AaBbCc and AaBbCc are crossed then AABBCC and aabbcc are two different dominant and recessive genomes seen in the offspring.
  • Offspring with AABBCC will be height whereas aabbcc will be dwarf. There will be offspring with different heights depending upon the dominant and recessive gene present in them.
  • Another genome produced are AABBCc/AaBBCC/AABbCC, next will have four dominant and 2 recessive, next will have 3 dominant and 3 recessive AaBbCc, next will have 2 dominant and 4 recessive, one dominant and five recessive. All together offspring produced will be 64
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Answer:

  1. E/e ; T/t  ⇒ Square eyes and long tail (Option D)
  2. 3/16 will have round eyes and long tails (Option C)
  3. 1/4 of the progeny will be heterozygous for both traits (Option A)

Explanation:

<u>Available data</u>:

  • Two diallelic unlinked genes
  • Gene E controls eye shape: Dominant allele E expresses square eyes, and recessive allele e expresses round eyes.
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<u>Genotypes                                          Phenotypes</u>

EETT, EeTT, EETt, EeTt                     Square eyes and Long tail

eeTT, eeTt                                          Round eyes and Long tail

EEtt, Eett                                             Square eyes and Short tail

eett                                                      Rounf eyes and short tail.

<em>1. An individual of this new species is heterozygous for gene E and heterozygous for gene T. What is their genotype and phenotype?</em>

The heterozygous individual is E/e ; T/t, expressing square eyes and a long tail.

<em>2. Two individuals, who are both heterozygous for eye shape and tail size, mate. Which of the following is a correct statement about the phenotype ratios expected for their offspring?</em>

Cross: between two heterozygous individuals

Parentals) EeTt    x     EeTt

Gametes) ET, Et, eT, et

                ET, Et, eT, et

Punnett square)  .   ET        Et        eT       et

                  ET     EETT    EETt    EeTT    EeTt

                  Et      EETt     EEtt     EeTt      Eett

                  eT    EeTT    EeTt    eeTT     eeTt

                   et     EeTt      Eett     eeTt      eett

F1) Genotype:

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  • 3/16 E-tt, Square eyes and short tails
  • 3/16 eeT-, Round eyes and Long tails
  • 1/16 eett, round eyes and short tail

Phenotypic ratio 9:3:3:1

<em>3. From the mating described in question ABOVE, what proportion of ALL of the offspring in will be heterozygous for both traits?</em>

4/16 = 1/4 = 25% of the progeny are expected to be heterozygous for both traits, EeTt.

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