Answer:
the inter-quartile range will increase
Step-by-step explanation:
The initial data-set was;
20,32,32,45,50
Adding a new value 78 will have several effects;
The mean of the new set of values will increase since 78 is mostly likely to be an outlier.
The median of the new data set will increase. The median of the old data set is 32 while that of the new data set will be 38.5
The mode is the most frequent observation. Both the new and the old sets of values will have a mode of 32. The mode will therefore remain the same.
The inter-quartile range just like the range will increase
f(x)=0
Domain are the set of x values
f(x)=0 , we find all the x values where y =0
At x intercepts y is always 0
so we find all the x intercepts.
x intercepts are the points where the graph crosses x axis
In the graph we can see that the graph crosses x axis at
-2.5 , -0.75 and 1
-2.5 , -0.75 and 1 are the domain where f(x)=0
We can solve this problem by first solving for the total
volume of the cube. The formula for volume of cube is given as:
V cube = s^3
Where s is the length of one side which is equivalent to
2 inches. Therefore:
V cube = (2 inches)^3
V cube = 8 cubic inch
Assuming that all the pebble fills the cube without any
spaces, then the total weight of the pebbles in the cube would simply be:
Total weight = 0.5 lb per cubic inch * 8 cubic inch
Total weight = 4 lb
Therefore, the total weight of the pebbles in the cube is <u>4
lbs</u>.
Answer:
honestly im not sure but i am doing that same work at the moment and i just ingore the m. it shouldnt change what you get as your answer.
