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tatuchka [14]
3 years ago
13

Which equation is equivalent to

Mathematics
2 answers:
jeka57 [31]3 years ago
8 0

Answer:

The answer is option 2.

Step-by-step explanation:

In the question, 16 and 81 are perfect squares. So in order to find the equivalent equation, you have to factorize it :

APPLY,

(a + b)(a - b) =  {a}^{2}  -  {b}^{2}

So for this question :

16 {x}^{4}  - 81 = 0

{(4 {x}^{2})}^{2} - {(9)}^{2}= 0

(4 {x}^{2}   +  9)(4 {x}^{2}  - 9) = 0

Aleksandr [31]3 years ago
5 0

Answer:

(4x^2 +9)(4x^2-9) =0

Step-by-step explanation:

16x^4 - 18 = 0

Rewriting

(4x^2)^2 - 9^2 =0

We notice that this is the difference of squares

a^2 - b^2 = (a-b)(a+b)

(4x^2 -9)(4x^2+9) =0

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prove that sin theta cos theta = cot theta is not a trigonometric identity by producing a counterexample
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Answer:

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Begin with the right hand side:

R.H.S = cot θ = \frac{cos \ \theta}{sin \ \theta}

L.H.S = sin θ cos θ

so, sin θ cos θ ≠ \frac{cos \ \theta}{sin \ \theta}

So, the equation is not a trigonometric identity.

=========================================================

<u>Anther solution:</u>

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Assume θ with a value and substitute with it.

Let θ = 45°

So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2

R.H.S = cot θ = cot 45 = 1

So, L.H.S ≠ R.H.S

So, sin θ cos θ = cot θ is not a trigonometric identity.

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3 years ago
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miss Akunina [59]

Both statements are true. Therefore (4,2) is a solution and option D is correct.

The given inequalities are y\leq 2x-2 and y\leq x^{2} -3x.

We need to select the point that is a solution to the system of inequalities (-2,-1), (1,3), (2,1) and (4,2).

<h3>What is an example of a system of inequalities in real life?</h3>

Inequalities can be seen in the speed limits on roads, the minimum age for seeing certain movies, and the distance you have to walk to go to the park. Inequalities represent a limit of what is permitted or achievable rather than a precise quantity.

Any point is a solution to this system of inequality if it satisfies both inequalities.

Check the inequalities by each option.

For (-2, -1), -1\leq 2(-2)-2 \implies -1\leq -6.

This statement is false because -1 is greater than -6. Therefore (-2,-1) is not a solution and option A is incorrect.

For (1, 3), 3\leq 2(1)-2 \implies 3\leq 0

This statement is false because 3 is greater than 0. Therefore (1,3) is not a solution and option B is incorrect.

For (2,1), 1\leq 2(2)-2 \implies 1\leq 2.

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This statement is false because 1 is greater than -2. Therefore (2,1) is not a solution and option C is incorrect.

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Both statements are true. Therefore (4,2) is a solution and option D is correct.

To learn more about inequalities visit:

brainly.com/question/20383699.

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irga5000 [103]
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