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Ratling [72]
2 years ago
11

Fuel for the reasearch vessels will be stored in a cylindrical tank with a radius of 10 meters and a height of 5 meters. Using a

pproximation of pocket to two decimal places, the volume of the tank is… place your approximation in the orange chart below
Mathematics
1 answer:
Lemur [1.5K]2 years ago
6 0

The volume of the tank is 1570 cubic meters

<h3>How to determine the volume</h3>

The formula for determining the volume of a cylinder is expressed as;

Volume = πr²h

Where;

  • radius is 10 meters
  • height is 5 meters
  • pi = 3. 14

Now, let's substitute into the formula;

Volume = 3. 14 × 10² × 5

Volume = 3. 14 × 100 × 5

Multiply through

Volume = 1570 cubic meters

Thus, the volume of the tank is 1570 cubic meters

Learn more about volume here:

brainly.com/question/1972490

#SPJ1

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=  \frac{ \theta}{180}  \times \pi \\  =  \frac{600}{180}  \times \pi \\  =  \frac{10}{3} \pi

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PLEASE HELP!!!
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Answer:

14-5i

Step-by-step explanation:

Distribute using FOIL

12+3i-8i-2i^2

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12+3i-8i-2(-1)

12+3i-8i+2

Combine like terms

14-5i

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Given the system of equations, what is the solution?
fredd [130]

The solution for the given equations  x + 3y = 5 and x - 3y = -1 are x=2 and y=1.

Step-by-step explanation:

The given is,

           x+3y=5......................................(1)

           x-3y=-1....................................(2)

Step:1

         By elimination method,

        Subtracting Equations (1) and (2),

                     x+3y=5

                     x-3y=-1

             ( - )

           ( x-x ) + ( 3y+3y ) = ( 5 +1 )

                                       6y = 6

                                         y = 1

Step:2

        Substitute the value of y in equation (1),

                             x+3y=5

                       x + ( 3 × 1 ) = 5

                                      x = 5-3

                                      x = 2

Step:3

        Check for Solution,

        Substitute the values of x and y in Eqn (1),

                                  x+3y=5

                           2 + ( 3 × 1 ) = 5

                                         5 = 5

Result:

       The solution for the given equations  x + 3y = 5 and x - 3y = -1 are x=2 and y=1, by elimination method.

7 0
3 years ago
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