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tamaranim1 [39]
3 years ago
13

6. a + 6 < -2; a = -8 I 0. yes P. no

Mathematics
1 answer:
laiz [17]3 years ago
4 0

Answer:

yes

Step-by-step explanation:

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4 0
3 years ago
The area of a rectangle is 42 ft squared, and the length of the rectangle is 5 ft more than twice the width. Find the dimensions
stira [4]

Answer:

<h3>Length = 12 ft</h3>

Width = \frac{7}{2} ft

Step-by-step explanation:

Given,

Area of rectangle = 42 \:  {ft}^{2}

Width = X

Length = 2x + 5

Now,

x(2x + 5) = 42

2 {x}^{2}  + 5x   = 42

2 {x}^{2}  + 5x - 42 = 0

2 {x}^{2}  + 12x - 7x - 42 = 0

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(2x  - 7)(x + 6) = 0

Either

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2x = 7

x =  \frac{7}{2}

Or,

x + 6 = 0

x = 0 - 6

x =  - 6

Negative value can't be taken.

So, width = \frac{7}{2} ft

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Finding the value of length,

Length = 2x + 5

2 \times  \frac{7}{2}  + 5

7 + 5

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