The total bill for the Cunningham family was $29.26.
Step-by-step explanation:
Step 1; First we total up the cost of the food alone. Mr. Cunningham spent $7.50, Mrs. Cunningham spent $6.25, the 2 children spent $4.99 each which equals $9.98 for both. So the total of the food alone was $23.73.
Step 2; The sales tax rate was 7.25% of the $23.73. So we multiply 0.0725 (7.25%) with the $23.73 which equals $1.72. So the total bill was for $23.73 + $1.72 which equals $25.45.
Step 3; The Cunningham family left a 15% tip. This was 15% of the toal bill which was $25.45. So we multiply 0.15 (15%) with $25.45 which equals $3.81. So the total bill was food cost + service tax + tips which is $23.73 + $1.72 + $3.81 = $29.26
Answer:
95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.
Step-by-step explanation:
Confidence interval is given by mean +/- margin of error (E)
Eggs from small nest
Sample size (n1) = 60
Mean = 37.2
Sample variance = 24.7
Eggs from large nest
Sample size (n2) = 159
Mean = 35.6
Sample variance = 39
Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11
Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93
Difference in mean = 37.2 - 35.6 = 1.6
Degree of freedom = n1+n2 - 2 = 60+159-2 = 217
Confidence level = 95%
Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132
E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79
Lower limit = mean - E = 1.6 - 0.79 = 0.81
Upper limit = mean + E = 1.6 + 0.79 = 2.39
95% confidence interval for the difference in average mass is (0.81, 2.39)
Answer:
0.875
Step-by-step explanation:
7/8 as a decimal is 0.875. Another was of thinking of this is the number '7' is 87.5 percent of the number '8.
If you are looking to evaluate the equation the answer is: 117
187 ft/s. I think that this might be an equation, but if it is not, I'm sorry.
