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Firdavs [7]
3 years ago
15

A certain freezing process requires that room temperature be lowered from 35oC at the rate of 6oC every hour. What will be the r

oom temperature 8 hours after the process begins?​
Mathematics
1 answer:
astra-53 [7]3 years ago
6 0

Answer:

-13 degrees celcius.

Step-by-step explanation:

6 degrees are lowered every hour. 6*8 = 48 degrees, 48 degrees are lowered.

35-48 is -13. The room temperature will be -13 eight hours after the process begins.

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BARSIC [14]

Answer:

x= 0 , \frac{1}{14} , \frac{-1}{12}

Step-by-step explanation:

Given, equation is \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x}. →→→ (1)

Now, by cubing the equation on both sides, we get

( \sqrt[3]{15x-1} + \sqrt[3]{13x+1} )³ = (4\sqrt[3]{x})³

⇒ (15x-1) + (13x+1) + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{15x-1} + \sqrt[3]{13x+1}) = 64 x.

⇒ 28x + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (4\sqrt[3]{x}) = 64x.        

(since from (1),  \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x})

⇒ 12× \sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{x})= 36x.

⇒ 3x = \sqrt[3]{(15x-1)(13+1)(x)}.

Now, once again cubing on both sides, we get

(3x)³ = (\sqrt[3]{(15x-1)(13+1)(x)})³.

⇒ 27x³ = (15x-1)(13x+1)(x).

⇒ 27x³ = 195x³ + 2x² - x

⇒ 168x³ + 2x² - x = 0

⇒ x(168x² + 2x -1) = 0

⇒ by, solving the equation we get ,

x = 0 ; x = \frac{1}{14} ; x = \frac{-1}{12}

therefore, solution is x= 0 , \frac{1}{14} , \frac{-1}{12}

7 0
3 years ago
Jason earned scores of 90 points, 82 points, 95 points, and 86 points on four tests. What is the lowest score he can get on the
dem82 [27]
97 points is your answer 3 hope this helps!
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What is the inverse of the function y=3e^(4x+1)
Sergeeva-Olga [200]
To find the inverse interchange the variables and solve for y

f^-1 (x) = - 1/4 + in(x)/4 - in(3)/4
6 0
3 years ago
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12 × (3 + 2²) ÷ 2 - 10
Lynna [10]

Answer:

32

Step-by-step explanation:

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3 years ago
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Find the midpoint of the segment between the points (8,-10) and (-10,-8)
Delvig [45]

Answer:

(-1, -9)

Step-by-step explanation:

Recall that for 2 points (x1, y1) and (x2,y2)

the midpoints are given by

x ordinate = \frac{x1+x2}{2}

y ordinate = \frac{y1+y2}{2}

In our case x1 = 8, y1 = -10, x2 = -10, y2=-8

x ordinate = \frac{x1+x2}{2}  = [8 + (-10) ] / 2 = -1

y ordinate = \frac{y1+y2}{2} = [-10 + (-8) ] / 2 = -9

hence midpoint is (-1, -9)

7 0
3 years ago
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