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maksim [4K]
2 years ago
5

Please help lolz ty besties

Mathematics
1 answer:
galben [10]2 years ago
4 0
24 players / B so the answer can be right
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In a single growing season at the smith family orchard, the average yield per apple tree is 150 apples when the number of trees
Mariana [72]

Answer:

100 trees should be planted per acre to maximize the total yield (15000 apples per acre)

Step-by-step explanation:

<u>Functions </u>

Expressing some quantities in terms of other(s) comes in handy to understand the behavior of the situations often modeled by those functions.

Our problem tells us about the smith family orchard, where the average yield per apple tree is 150 apples when the number of trees per acre is 100 (or less). But the average yield per tree decreases when more than 100 trees are planted. The rate of decrease is 1 for each additional tree is planted

Let's call x the number of trees planted per acre in a single growing season. We have two conditions when modeling:  when x is less than 100, the average yield per apple tree (Ay) is (fixed) 150.

Ay(x)=150\ ,\ x\leqslant 100

When x is more than 100:

Ay(x)=150-x\ ,\ 100< x\leqslant 150

The upper limit is 150 because it would mean the Average yield is zero and no apples are to be harvested

Part 1

We are asked what happens if the number of trees per acre was doubled, but we don't know what the original number was. Let's make it x=60

If x=60, then we must use the first function, and

Ay(60)=150

The yield per acre will be 150*60=9000 apples

If we doubled x to 120, we would have to use the second function

Ay(120)=150-x=30

The yield per acre will be 30*120=3600 apples

Note that doubling the number of trees would make the production decrease

If we started with x=30, then  

Ay(30)=150, and we would have 150*30=4500 apples per acre

We already know that for x=60 (the double of 30), our production will be 9000 apples per acre

This shows us that in some cases, increasing the number of trees is beneficial and in other cases, it is not

Part 2

The total yield is computed as

Y(x)=x.Ay(x)

This function will be different depending on the value of x

Y(x)=150x\ ,\ x\leqslant 100

Y(x)=150x-x^2\ ,\ 100< x\leqslant 150

To find the maximum total yield we take the first derivative

Y'(x)=150\ ,\ x\leqslant 100

Y'(x)=150-2x\ ,\ 100< x\leqslant 150

The first expression has no variable, so the total yield must be evaluated in the endpoints

Y(0)=0

Y(100)=15000

Now, the second expression contains variable, it will be set to 0 to find the critical point

150-2x=0

x=75

x is outside of the boundaries, we cannot find the maximum in this interval

Answer: 100 trees should be planted per acre to maximize the total yield (15000 apples per acre)

7 0
3 years ago
What is the total of all 3 tickets below. use the menu to solve
alex41 [277]

Answer:

$103.14

Step-by-step explanation:

The calculation of slips are amounted to a total of $103.14

5 0
2 years ago
Is the number of points scored during a basketball game a discrete random​ variable, a continuous random​ variable, or not a ran
monitta

Answer: Option (B) is correct.

Step-by-step explanation:

The number of points scored during a basketball game is a discrete random variable.

Discrete Random variable:

A discrete random variable is a variable whose value can be evaluated by counting. It is also referred as a countable and finite values. Examples of discrete random variable are as follows:

-The quantity of runs scored during a ball game  

- Number of hits a site gets during seven days  

- Number of lights that wear out in the following year in a stay with 13 bulbs  

- Number of pigeons in a city  

- Number of free-toss endeavors before the principal shot is missed

3 0
3 years ago
Read 2 more answers
A system of equations is shown below
KatRina [158]

Answer:

D Multiply equation B by 5 and equation A by 4 and add the results together

7 0
2 years ago
Use the figure to find the measures of the numbered angles. ∠5 = ∠6 =
Gwar [14]

Answer:

∠ 5 = 49°, ∠ 6 = 131°

Step-by-step explanation:

∠ 5 and 49° are corresponding angles and are congruent, then

∠ 5 = 49°

∠ 5 and ∠ 6 are adjacent angles and are supplementary, sum to 180° , that is

∠ 6 + ∠ 5 = 180°

∠ 6 + 49° = 180° ( subtract 49° from both sides )

∠ 6 = 131°

5 0
3 years ago
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