Ask question

Ask question

All categories

3 years ago

5

Dominics two daughters both want to take gymnastics this year. It cost 90 per month per child. How much dose dominic need to bud

get for a year ( 12 months) of gymnastics for both daughters

1 answer:

CaHeK987 [17]3 years ago

6 0

Answer:

$2,160 is what he need for both daughters for 1 year

Step-by-step explanation:

90 x 2 = 180

180 x 12 = 2,160

You might be interested in

A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and

mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

$\mu = \frac{3X_{1} + 4X_{2} }{8}$

Now

Bias for the estimator = E(μ bar) - μ

= $E( \frac{3X_{1} + 4X_{2} }{8}) - 4.5$

= $\frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5$

= $\frac{3(4.5) + 4(4.5)}{8} - 4.5$

= $\frac{13.5 + 18}{8} - 4.5$

= $\frac{31.5}{8} - 4.5$

= 3.9375 - 4.5

= - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

= Var(μ bar) + [Bias(μ bar, μ)]²

= $Var( \frac{3X_{1} + 4X_{2} }{8}) + 0.3136$

= $\frac{1}{64} Var( {3X_{1} + 4X_{2} }) + 0.3136$

= $\frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})] }) + 0.3136$

= $\frac{1}{64} [{3(57.76) + 4(57.76)}] } + 0.3136$

= $\frac{1}{64} [7(57.76)}] } + 0.3136$

= $\frac{1}{64} [404.32] } + 0.3136$

= $6.3175 + 0.3136$

= 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

6 0

3 years ago

Hello, PLEASE ANSWER ASAP!!! Don't report my question or give me false answers but I'm freaking out. I was biking home from scho

faltersainse [42]

Answer:

Kuroo Here!

Step-by-step explanation:

Just Tell the truth. Your parents don't want you do die. So Just say the truth. There is nothing good after telling lies.

5 0

3 years ago

Read 2 more answers

Factorise 9a^2 - 6ab + 12ac - 8bc

Lady_Fox [76]

9a^2-6ab+12ac-8bc
=3a(3a-2b)+4c(3a-2b)
=(3a+4c)(3a-2b)
There you go. Have fun!

6 0

3 years ago

How are percent transmittance and absorbance related algebraically?

statuscvo [17]

Answer:

So, if all the light passes through a solution without any absorption, then absorbance is zero, and percent transmittance is 100%. If all the light is absorbed, then percent transmittance is zero, and absorption is infinite.

Absorbance is the inverse of transmittance so,

A = 1/T

Beer's law (sometimes called the Beer-Lambert law) states that the absorbance is proportional to the path length, b, through the sample and the concentration of the absorbing species, c:

A ∝ b · c

As Transmittance, $T =\dfrac{P}{P_0}$

% Transmittance, $\%T=100\times T$

Absorbance,

$A=\log_{10} \dfrac{P_0}{P}\\\\A =\log_{10}\times \dfrac{1}{T}\\\\A=\dfrac{\log_{10} 100}{\%T}\\\\A=(2 - log_{10})\times \%T$

Hence, $A=\log_{10}\times \dfrac{1}{T}$ is the algebraic relation between absorbance and transmittance.

8 0

3 years ago

Which numeration system is also known as 10 base numeration system

Kobotan [32]

Answer:

decimal system

..........

8 0

3 years ago